Ask question

Ask question

All categories

3 years ago

13

What mechanical layer lies below the lithosphere

2 answers:

ipn [44]3 years ago

7 0

Answer: The layer below the lithosphere lies the Asthenosphere.

Explanation:

The asthenosphere is a viscous layer, in which the rocks are solid but has the ability to slightly flow due to deformation. This layer plays a very significant role in the plate tectonic movement, which initiates the motion of the lithospheric crust, due to the generation of the convection current at the mantle. It is present in the upper part of the mantle.

The internal heat from the core of the earth radiates to the mantle, and the magma at the mantle gets heated up and become less dense and rises up, and this magma when reaches on the upper part of the mantle, near the surface, gets cools down and become more dense, and sinks. This continuous circulation of magma in the mantle region is known as the convection current.

joja [24]3 years ago

3 0

The <span>asthenosphere is under the lithosphere.</span>

You might be interested in

4. Mrs. Parker was married to her husband for

Leokris [45]

<h3>Answer:</h3><h3>B ) Nuclear family</h3>

Explanation:

The answer is B because Nuclear family mean a family with two kids and Mrs. Parker have two kids

5 0

3 years ago

A 0.0382-kg bullet is fired horizontally into a 3.78-kg wooden block attached to one end of a massless, horizontal spring (k = 8

wel

Answer:

$280.87$ ms⁻¹

Explanation:

Consider the motion of the bullet-block combination after collision

$m$ = mass of the bullet = 0.0382 kg

$M$ = mass of wooden block = 3.78 kg

$V$ = velocity of the bullet-block combination after collision

$k$ = spring constant of the spring = 833 N m⁻¹

$A$ = Amplitude of oscillation = 0.190 m

Using conservation of energy

Kinetic energy of bullet-block combination after collision = Spring potential energy gained due to compression of spring

$(0.5)(m + M)V^{2} = (0.5)kA^{2}$

$(0.0382 + 3.78)V^{2} = (833)(0.190)^{2}$

$V = 2.81$ ms⁻¹

$v_{o}$ = initial velocity of the bullet before striking the block

Using conservation of momentum for the collision between bullet and block

$m v_{o} = (m + M) V$

$(0.0382) v_{o} = (0.0382 + 3.78) (2.81)$

$v_{o} = 280.87$ ms⁻¹

7 0

3 years ago

A 20-kg block slides down a fixed rough curved track The block has a speed of 5 0 m/s after its height above a horizontal surfac

Crank

Answer:

U = 102.8 J (100 J to two significant digits)

Explanation:

potential energy converted = 20(9.8)(1.8) = 352.8 J

kinetic energy at base of track = ½(20)5.0² = 250 J

energy (work) of friction 352.8 - 250 = 102.8 J

8 0

3 years ago

Is a balance scale used to describe how much matter is in an object

gtnhenbr [62]

It's used to measure the mass or weight of an object

7 0

3 years ago

Read 2 more answers

The clouds in the sky appear to be white because the clouds _____?

scZoUnD [109]

D. White is a reflectiom of all colors

3 0

3 years ago