Question

HELP!!! I need help in simplifying this question.

Answer 1

Answer: $x^{-4}=\frac{1}{x^{4}}$

Step-by-step explanation:

We have the following expression:

$(\sqrt[3]{x^{2}} \sqrt[6]{x^{4}})^{-3}$

Which can also be written as:

$(x^{\frac{2}{3}} x^{\frac{4}{6}})^{-3}$

Since we have exponents with the same base $x$ inside the parenthesis, we can sum both exponents:

$(x^{\frac{4}{3}})^{-3}$

Now, we have to multiply the exponent out of the parenthesis with the inner exponent and have the following result:

$x^{-4}=\frac{1}{x^{4}}$