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Marysya12 [62]
3 years ago
6

The ratio of seventh graders to sixth graders on a chess team is 5 to 3 . What is the ratio of seventh graders to total chess pl

ayers ? Enter the correct answer in the box
Mathematics
1 answer:
stepladder [879]3 years ago
8 0

Answer: 5 : 8

Step-by-step explanation:

The ratio of seventh graders to sixth grader on the team is 5 : 3.

Assuming that only seventh and sixth graders are in the team, the total number of chess players at the most simple basis is:

= Number of seventh grade students in ratio + Number of sixth grade students in ratio

= 5 + 3

= 8 students

There are 5 seventh graders so the ratio will be:

= 5 : 8

<em>Note: The chess team will most likely have more than 8 members but the  ratio of seventh graders to total chess players will still be 5 : 8. </em>

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Derrick is training for a race he wants to run a total of 100 miles over 4 weeks he only runs 16 miles in the first week if he r
Gala2k [10]

Answer:

  28 miles

Step-by-step explanation:

Let w stand for the number of miles Derrick runs each week. Then after 4 weeks of training, he wants the total mileage to be 100 miles.

  16 + 3w = 100

  3w = 84 . . . . . . . subtract 16

  w = 28 . . . . . . . . divide by 3

Derrick will run 28 miles each week to achieve his training goal.

7 0
3 years ago
Need some help please <br><img src="https://tex.z-dn.net/?f=%20%5Cfrac%7B11%7D%7B15%7D%20%20%2B%20%28%20-%20%20%5Cfrac%7B3%7D%7B
emmasim [6.3K]

Answer:

-1/60

Step-by-step explanation:

\frac{11}{15}  + (- \frac{3}{4} )\\

= \frac{11}{15}  -  \frac{3}{4}\\

= \frac{44}{60}  -  \frac{45}{60}\\  (find LCM of demoninators)

= \frac{44-45}{60}\\

= \frac{-1}{60}\\

= -1/60

7 0
3 years ago
Please help me someone!
Elena-2011 [213]

Answer:

That looks hard but idk how to answer it

Step-by-step explanation:


8 0
3 years ago
Give a 98% confidence interval for one population mean, given asample of 28 data points with sample mean 30.0 and sample standar
klio [65]

We have a sample of 28 data points. The sample mean is 30.0 and the sample standard deviation is 2.40. The confidence level required is 98%. Then, we calculate α by:

\begin{gathered} 1-\alpha=0.98 \\ \alpha=0.02 \end{gathered}

The confidence interval for the population mean, given the sample mean μ and the sample standard deviation σ, can be calculated as:

CI(\mu)=\lbrack x-Z_{1-\frac{\alpha}{2}}\cdot\frac{\sigma}{\sqrt[]{n}},x+Z_{1-\frac{\alpha}{2}}\cdot\frac{\sigma}{\sqrt[]{n}}\rbrack

Where n is the sample size, and Z is the z-score for 1 - α/2. Using the known values:

CI(\mu)=\lbrack30.0-Z_{0.99}\cdot\frac{2.40}{\sqrt[]{28}},30.0+Z_{0.99}\cdot\frac{2.40}{\sqrt[]{28}}\rbrack

Where (from tables):

Z_{0.99}=2.33

Finally, the interval at 98% confidence level is:

CI(\mu)=\lbrack28.94,31.06\rbrack

4 0
1 year ago
In the set, (1,4), (3,5) and (-1, 2), what is the range?
stealth61 [152]

Answer:

\boxed{ \bold{ \huge{ \boxed{ \sf{2 \: ,  \: 4 \: ,  \: 5 \: }}}}}

Step-by-step explanation:

Given,

{ 1 , 4 } , { 3 , 5 } , { - 1 , 2 }

To find : Range

<u>Range are the set of all y - co-ordinates .</u>

So,

Answer : { 2 , 4 , 5 }

Hope I helped!

Best regards!

4 0
3 years ago
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