Answer:
Step-by-step explanation:
Work is said to be done when a force applied to an object cause the body to move in a specified direction.
Work-done = Force * Distance
Since Force = mass * acceleration due to gravity
Work-done = mass * acceleration due to gravity * distance
Given mass = 1.4kg, distance = 0.7m and g = 9.8m/s²
Workdone in lifting the book off the floor = 1.4*0.7*9.8
Workdone = 9.604Joules
- Similarly, work done in lifting a 21-lb weight book 6 ft off the ground is expressed using the same formula as above;
Given mass = 21-lb, g = 32ft/s² and distance = 6ft
Workdone = 21 * 32 * 6
Workdone = 4,032 lb-ft²/s²
Hence, work-done in lifting a 21-lb weight book 6 ft off the ground is 4,032 lb-ft²/s²
( 1 - x/100)^20 = 3843/55550
Taking logs
20 log (1 - x/100) = log (3843/55550)
log ( 1 - x/100) = log (3843/55550) / 20 = -0.0580007
1 - x/100 = 10^-0.0580007 = 0.875
x / 100 = 1 - 0.875 = 0.125
x = 12.5 Answer
The answer would be where the points meet.
In this case it would be (1,-1)
Answer:
Step-by-step explanation:
Answer:
Step-by-step explanation:
the first method :
s(x) = 2 - x and f(x) = 3x
(s f) (-7) = s(-7) ×f(-7)
but : s(-7) = 2 - (-7) =2+7 = 9
f(-7) = 3(-7) = - 21
so : (s f) (-7) = (9)×(-21) = - 189
the second method :
calculate : (s f) (x) == s(x)×f(x) = (2-x) 3x = 6x - 3x²
(s f) (-7) = 6(-7) -3 (-7)² = - 42 -147 = -189
