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Tresset [83]
3 years ago
8

-What is the frequency of a 5.6 x 10^10 cm wave? -What is the wavelength of 0.1096 Hz wave?

Chemistry
1 answer:
bixtya [17]3 years ago
3 0
The equation that we will use to solve these two questions is:
c = lambda * f where:
c is the speed f the wave
lambda is the wavelength of the wave
f is the frequency of the wave

Question 1:
we want to find f
c is assumed to be the speed of light = 3*10^8 m/sec
lambda = 5.6 * 10^10 cm = 560 * 10^6 meters
Substitute in the equation to get f as follows:
3*10^8 = 560*10^6*f
f = (3*10^8) / (560*10^6) = 0.5357 Hz

Question 2:
we want to find lambda
c is assumed to be the speed of light = 3*10^8 m/sec
f is given as 0.1096 Hz
Substitute in the equation to get lambda as follows:
3*10^8 = lambda * 0.1096
lambda = (3*10^8) / (0.1096) = 2.737226*10^9 meters
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Answer:

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Explanation:

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4 0
2 years ago
You have 125.0 mL of a solution of H3PO4, bu you don't know its concentration. if you titrate the solution with a 4.56-M solutio
irakobra [83]

Answer:

4.90 M

Explanation:

In case of titration , the following formula can be used -

M₁V₁ = M₂V₂

where ,

M₁ = concentration of acid ,

V₁ = volume of acid ,

M₂ = concentration of base,

V₂ = volume of base .

from , the question ,

M₁ = ? M

V₁ = 125.0 mL

M₂ = 4.56 M

V₂ = 134.1 mL

Using the above formula , the molarity of acid , can be calculated as ,

M₁V₁ = M₂V₂  

Substituting the respective values ,  

M₁ *  125.0 mL = 4.56 M *  134.1 mL

M₁ = 4.90 M

6 0
3 years ago
Calculate the number of ammonia molecules in 3.9 g.
disa [49]
•3.9g of ammonia
•molar mass of ammonia = 17.03g/mol

1st you have to covert grams to moles by dividing the mass of ammonia with the molar mass:

(3.9 g)/ (17.03g/mol) = 0.22900763mols

Then convert the moles to molecules by multiplying it with Avogadro’s number:

Avogadro’s number: 6.022 x 10^23


0.22900763mols x (6.022 x 10^23 molecs/mol)
= 1.38 x 10^23 molecules
6 0
3 years ago
A gas has a pressure of 853.0 millibars at a temperature of 29.0 °C. If the volume is unchanged but the temperature is increased
Nitella [24]

The new pressure of the gas that initially have a pressure of 853.0 millibars at a temperature of 29.0 °C is 1011.17 millibars. Details about pressure can be found below.

<h3>How to calculate pressure?</h3>

The pressure of a given gas can be calculated using the following formula:

P1/T1 = P2/T2

Where;

  • P1 = initial pressure = 853.0 millibars
  • P2 = final pressure = ?
  • T1 = initial temperature = 29°C + 273 = 302K
  • T2 = final temperature = 85°C + 273 = 358K

853/302 = P2/358

358 × 853 = 302P2

305374 = 302P2

P2 = 305374 ÷ 302

P2 = 1011.17 millibars

Therefore, the new pressure of the gas that initially have a pressure of 853.0 millibars at a temperature of 29.0 °C is 1011.17 millibars.

Learn more about pressure at: brainly.com/question/15175692

#SPJ1

8 0
2 years ago
What substance does a tree use for food
Lera25 [3.4K]

Answer:        Your Answer is carbon dioxide, water, nutrients, and energy from sunlight.

6 0
3 years ago
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