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Mkey [24]
1 year ago
5

4.a) Draw two Lewis structures for HCP; one where C is central and one where P is central: b) Calculate formal charge for each a

tom in each structure: Which structure is favored? Explain your answer: 5. a) Draw all possible resonance structures for HCOSel (C is central) b) Calculate formal charge for each atom in each structure: Which structure is favored? Explain your answer:
Chemistry
1 answer:
love history [14]1 year ago
8 0

One Hydrogen atom (H) and one Oxygen atom (O) surround the central Carbon atom (C) in the HCP Lewis structure (O). Carbon (C) and Phosphorus (P) have a triple bond, and Carbon (C) and Hydrogen (H) have a single bond.

<h3>How can you choose the ideal format for a formal charge?</h3>

The Lewis structure with the negative formal charges on the most electronegative atoms is the one to choose from when faced with a choice between numerous Lewis structures with similar formal charge distributions.

<h3>How do you determine the preferred resonance structure?</h3>

The resonance forms with the fewest non-zero formal charge atoms are selected. Resonance develops atoms that have a negative formal charge or are the most electronegative are preferred.

To know more about Lewis structure visit:-

brainly.com/question/20300458

#SPJ4

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Uranium-267 undergoes alpha decay, what is the mass of the new element?
Firlakuza [10]

Answer:

will this help ?

Explanation:

(108Hs) is a synthetic element, and thus a standard atomic weight cannot be given. Like all synthetic elements, it has no stable isotopes. The first isotope to be synthesized was 265Hs in 1984. There are 12 known isotopes from 263Hs to 277Hs and 1–4 isomers. The most stable isotope of hassium cannot be determined based on existing data due to uncertainty that arises from the low number of measurements. The confidence interval of half-life of 269Hs corresponding to one standard deviation (the interval is ~68.3% likely to contain the actual value) is 16 ± 6 seconds, whereas that of 270Hs is 9 ± 4 seconds. It is also possible that 277mHs is more stable than both of these, with its half-life likely being 110 ± 70 seconds, but only one event of decay of this isotope has been registered as of 2016.[1][2].

3 0
3 years ago
Complete combustion of 5.90 g of a hydrocarbon produced 18.8 g of CO2 and 6.75 g of H2O.
Inessa05 [86]
First we have to find moles of C:
Molar mass of CO2:
12*1+16*2 = 44g/mol
(18.8 g CO2) / (44.00964 g CO2/mol) x (1 mol C/ 1 mol CO2) =0.427 mol C 
Molar mass of H2O:
2*1+16 = 18g/mol
As there is 2 moles of H in H2O,
So,

<span>(6.75 g H2O) / (18.01532 g H2O/mol) x (2 mol H / 1 mol H2O) = 0.74mol H </span>

<span>Divide both number of moles by the smaller number of moles: </span>
<span>As Smaaler no moles is 0.427:
So,
Dividing both number os moles by 0.427 :
(0.427 mol C) / 0.427 = 1.000 </span>
<span>(0.74 mol H) / 0.427 = 1.733 </span>

<span>To achieve integer coefficients, multiply by 2, then round to the nearest whole numbers to find the empirical formula: 
C = 1 * 2 = 2
H = 1.733 * 2 =3.466
So , the empirical formula is C2H3</span>
4 0
3 years ago
Read 2 more answers
The heat required to raise the temperature of 12g of water from 16 C to 21 C is:
NemiM [27]

Answer:

The heat required to raise the temperature of 12g of water from 16 C to 21 C is 60 cal.

Explanation:

Calorimetry is the measurement and calculation of the amounts of heat exchanged by a body or a system.

There is a direct proportional relationship between heat and temperature. The constant of proportionality depends on the substance that constitutes the body as on its mass, and is the product of the specific heat by the mass of the body. So, the equation that allows calculating heat exchanges is:

Q = c * m * ΔT

where Q is the heat exchanged by a body of mass m, made up of a specific heat substance c and where ΔT is the temperature variation.

In this case, you know:

  • Q=?
  • c= 4.186 \frac{J}{g*C}
  • m= 12 g
  • ΔT=Tfinal - Tinitial= 21 °C - 16°C= 5 °C

Replacing:

Q= 4.186 \frac{J}{g*C} *12 g *5 °C

Solving:

Q=251.16 J

Since 1 J is equal to 0.2388 cal, then the following rule of three can be applied: if 1 J is equal to 0.2388 cal, then 251.16 J to how many cal are?

cal=\frac{251.16 J * 0.2388 cal}{1 J}

cal= 59.98 ≅ 60

<u><em>The heat required to raise the temperature of 12g of water from 16 C to 21 C is 60 cal.</em></u>

3 0
3 years ago
In a unimolecular reaction with twice as much starting material as product at equilibrium, what is the value of Keq? Is ΔG o pos
lubasha [3.4K]

Answer : The value of K_{eq} is, 0.5 and \Delta G= positive.

Explanation :

The unimolecular reaction is:

A\rightarrow B

In unimolecular reaction, the starting material is 2 times to the product.

A=2B      .........(1)

As we know that:

K_{eq}=\frac{B}{A}     ...........(2)

Now substitute equation 1 in 2, we get:

K_{eq}=\frac{\frac{A}{2}}{A}

K_{eq}=0.5

Now we have to calculate the value of \Delta G^o at 298 K.

\Delta G^o=-RT\ln K_{eq}

where,

\Delta G^o = standard Gibbs free energy = ?

R = gas constant = 8.314 J/mol.K

T = temperature = 298 K

K_{eq} = equilibrium constant = 0.5

Now put all the given values on the above formula, we get:

\Delta G^o=-(8.314J/mol.K)\times (298K)\ln (0.5)

\Delta G^o=1717.32J/mol

Thus, the value of \Delta G^o at 298 K is, 1717.32 J/mol

As we know that:

\Delta G= +ve, reaction is non spontaneous

\Delta G= -ve, reaction is spontaneous

\Delta G= 0, reaction is in equilibrium

Thus, the \Delta G= +ve. So, the reaction is non spontaneous.

8 0
3 years ago
Which energy transformation produces electricity and is least likely to negatively impact the environment?
Anastasy [175]

<em>Hello!</em>

<h3><em /></h3><h3><u><em>The answer to this question is</em></u>: D) Generating electricity from a solar panel system.</h3><h3 />

<em><u>Thank you for asking this question!</u></em>

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<em><u /></em>

<em><u>It would be greatly appreciated if you thanked me and marked me as the brainliest!</u></em>

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<em><u>Have an amazing day.</u></em>

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8 0
3 years ago
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