Answer:
The distance between Harry’s home and his office? is 15 miles.
Step-by-step explanation:
The speed, distance time formula is:

Given:
Speed (<em>s</em>) = 30 miles/hour
Then the relation between distance and time is:

If Speed was 60 miles/hour the time taken is
hours.
Then the relation between distance and time is:

Use the value of <em>d</em> = 30t in (ii)
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Determine the distance as follows:

Thus, the distance between Harry’s home and his office? is 15 miles.
, that is D
when multiplying like variables add the exponents
=
= 
15u - 12u = 5
First combine like terms
3u = 5
Then isolate the variable by dividing both sides by 3
u = 5/3
u = 1 2/3
Hope this helped!
-TTL