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Gwar [14]
3 years ago
15

What is the value of x? 3x - x + 4 = 4(2x - 1)

Mathematics
1 answer:
Anton [14]3 years ago
8 0
3x−x+4=4(2x−1)
Step 1: Simplify both sides of the equation.<span><span><span><span>3x</span>−x</span>+4</span>=<span>4<span>(<span><span>2x</span>−1</span>)</span></span></span><span>Simplify: (Show steps)</span><span><span><span>2x</span>+4</span>=<span><span>8x</span>−4</span></span>Step 2: Subtract 8x from both sides.<span><span><span><span>2x</span>+4</span>−<span>8x</span></span>=<span><span><span>8x</span>−4</span>−<span>8x</span></span></span><span><span><span>−<span>6x</span></span>+4</span>=<span>−4</span></span>Step 3: Subtract 4 from both sides.<span><span><span><span>−<span>6x</span></span>+4</span>−4</span>=<span><span>−4</span>−4</span></span><span><span>−<span>6x</span></span>=<span>−8</span></span>Step 4: Divide both sides by -6.<span><span><span>−<span>6x/</span></span><span>−6</span></span>=<span><span>−8/</span><span>−6</span></span></span><span>x=<span>4/3</span></span>Answer:<span>x=<span>4/<span>3</span></span></span>
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You have 2,112 grams of a radioactive kind of mercury. How much will be left after 188 days if it's half-life is 47 days?
Anastasy [175]

Answer:

  • 132 g

Step-by-step explanation:

  • Initial amount = 2112 g
  • Time = 188 days
  • Half-life = 47 days

188 days / 47 days = 4 periods

<u>Mercury left after 188 days:</u>

  • 2112 * (1/2)^4 =
  • 2112* 1/16 =
  • 2112/16 =
  • 132 g

4 0
2 years ago
Given: BDis a diameter<br> m 1 = 100°<br> m BC= 30°<br><br> m2 =<br><br> 30<br> 80<br> 100
skad [1K]

Answer:

∠2 = 80°

Step-by-step explanation:

Since BD is a diameter then

∠1 + ∠2 = 180°, that is

100° + ∠2 = 180° ( subtract 100° from both sides )

∠2 = 180° - 100° = 80°

4 0
3 years ago
Read 2 more answers
The perimeter of a regular pentagon is 41.5 cm. Write and solve an equation to determine the length of each side of the pentagon
Sveta_85 [38]

Answer:

41.5÷5= the answer 8.3 cm

5 0
3 years ago
Find the first, fourth, and eighth terms of the sequence. A(n) = –3 • 2^n–1
Sphinxa [80]
A(n) = –3 • 2⁽ⁿ⁻¹⁾

for n = 1 ,  A₁ = -3.(2)⁰ = -3
for n = 2 ,  A₂ = -3.(2)¹ = -6
for n = 3 ,  A₃ = -3.(2)² = -12
for n = 4 ,  A₄ = -3.(2)³ = -24
...........................................
for n = 8 ,  A₈ = -3.(2)⁷ = -384


4 0
2 years ago
Use the markings in the image to answer the following questions (drawing not to scale):
katrin [286]

First of all, we have to observe this triangles separated by the height. These small and big triangles are similar according to the Angle-Angle-Angle principle.


a. We can find all of these length using the cosine of the angle, Pythagoras theorem and the principle of the similarity of triangles.


b. According to the cosine of the angle we can write that, cosθ = 12/a = 5/13 and from here a = 31.2. After finding that using Pythagoras theorem, we can write that b=\sqrt{31.2^{2}-12^{2}} = 28.8. According to the similarity of the triangles, we can write that 31.2/d = 28.8/12 and d = 13. Applying Pythagoras theorem we find that c = 5.


c. We already gave the answer for this question in part b


8 0
3 years ago
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