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jek_recluse [69]
3 years ago
9

What is the area of the triangle?​

Mathematics
1 answer:
Delvig [45]3 years ago
6 0

Answer: 10 units squared

Step-by-step explanation: you would multiply 4 by 5 and then you divide by two/ multiply by 1/2 and then you get an area of 10 units squared please mark me as brainliest

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Thanks for your help! :)
Tanya [424]

Answer:

65 = 6x + 7

6x = 58

x = 9.6666666...

65 + y + 9 = 180

y = 106


Step-by-step explanation:


4 0
3 years ago
In one month, Jillian made 36 local phone calls and 20 long distance calls.
Rufina [12.5K]
Local Calls = 36
Distance calls = 20

Ratio would be: = 36/20 = 18/10 = 9/5

In short, Your Answer would be Option A

Hope this helps!
4 0
3 years ago
A data analyst wants to set up a hypothesis test to determine if the mean number of courses taken in a college semester is diffe
Nadya [2.5K]

Answer:

Step-by-step explanation:

Hello!

What you want to test is if there is a difference between the number of courses taken by students of different years, you can determine 4 populations of students:

Population 1: Freshmen

Population 2: Sophomores

Population 3: Juniors

Population 4: Seniors

To each population you measured the study variable, setting 4 different variables. To compare these variables the best way is to make one test where you compare the four populations at the same time, so the hypothesis is:

H₀: μ₁ = μ₂ = μ₃ = μ₄

H₁: At least one of the population means is different from the others.

The most appropriate test to use to compare the population mean of the 4 groups is an ANOVA.

I hope you have a SUPER day!

3 0
4 years ago
A particle moves along a line with acceleration a (t) = -1/(t+2)2 ft/sec2. Find the distance traveled by the particle during the
amm1812

Answer:

s(t)=(ln|7|+ln|2|)\,ft

Step-by-step explanation:

Acceleration is second derivative of distance and are related as:

a(t)=\frac{d^2s}{dt^2}\\\\\frac{d^2s}{dt^2}=\frac{-1}{(t+2)^2}\\

Integrating both sides w.r.to t

v(t)=\frac{ds}{dt}=\frac{1}{t+2} +C\\

Using initial value

v(0)=\frac{1}{2}\\\\\frac{1}{2}=\frac{1}{0+2} +C\\\\C=0\\\\\frac{ds}{dt}=\frac{1}{t+2}

We have to calculate the distance covered in time interval [0,5], so:

\int\limits^5_0 \frac{ds}{dt}=\int\limits^5_0 {\frac{1}{t+2}} \, dt\\\\s(t)=[ln|t+2|]^5_0\\\\s(t)=ln|5+2|+ln|0+2|\\\\s(t)=(ln|7|+ln|2|)\,ft

3 0
3 years ago
Ahmad is choosing a password to access his teacher’s web page. He must choose a capital letter and three non-repeating digits fr
BaLLatris [955]

Answer:

Step-by-step explanation:

are there options?

7 0
4 years ago
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