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professor190 [17]
3 years ago
8

Which is an example of a statistical question?

Mathematics
2 answers:
Elis [28]3 years ago
4 0

Answer:

what is your favorite kind of pet! :)

Step-by-step explanation:

Flauer [41]3 years ago
3 0

Answer:

(A) Question 1

Step-by-step explanation:

You might be interested in
A sphere is just enclosed inside a right circular cylinder. If the volume of the sphere is 140 cm3, find the volume of the gap b
alexgriva [62]
-----------------------------------------------------------
Find Radius :
-----------------------------------------------------------
\text {Volume of a sphere =}   \dfrac{4}{3}  \pi r^3

\dfrac{4}{3}  \pi r^3 = 140

\pi r^3 = 140 \times  \dfrac{3}{4}

\pi r^3 = 105

r^3 =  \dfrac{105}{ \pi}

r = 3.22 \ cm

-----------------------------------------------------------
Find volume of the cylinder :
-----------------------------------------------------------
\text {Volume of the cylinder = } \pi r^2h

\text {Volume of the cylinder = } \pi ((3.22)^2(3.22 \times 2)

\text {Volume of the cylinder = } 209.77 \ cm^3

-----------------------------------------------------------
Find volume of the gap :
-----------------------------------------------------------
\text {Volume of gap = } 209.77 - 140

\text {Volume of gap = } 69.77 \ cm^3

-----------------------------------------------------------
\bf \text {Answer : } 69.77 \cm^3
-----------------------------------------------------------

6 0
3 years ago
Extra points and top BRAINIEST!!Lorie correctly determines that for the triangles below, the statement and the statement both de
Allushta [10]

The rest of the question is the attached figure

========================================

solution:

========

As show in the attached figure


∠M = ∠R = 54.4°


∠N = ∠T = 71.2°


∠O = 180° - (∠M + ∠N) = 180° - (54.4°+71.2°) = 54.4°


∠S = 180° - (∠R + ∠T) = 180° - (54.4°+71.2°) = 54.4°


∠O = ∠S = 36°


∴ Δ MNO is similar to Δ RTS


So, the correct statement:


The triangles each have two given angle measures and one unknown angle measure.



3 0
3 years ago
PLEASE HELP ME WITH THIS THANKS
Zarrin [17]

Answer:

The answer to your question is SA =  2419.34 m²

Step-by-step explanation:

Data

a = 11.42 m

side = 11 m

height = 20 m

Formula

SA = 2B + PH

Process

1.- Calculate P

Perimeter = P

P = 7(11)

  = 77 m

2.- Calculate B

B = Pa/2

   = (77)(11.42)/2

   = 879.34/2

   = 439.67 m²

3.- Calculate 2B

2B = 2(439.67)

    = 879.34 m²

4.- Calculate PH

PH = (77)(20)

     = 1540 m²

5.- Calculate SA

SA = 879.34 + 1540

     = 2419.34 m²

4 0
3 years ago
Read 2 more answers
The Wall Street Journal Corporate Perceptions Study 2011 surveyed readers and asked how each rated the Quality of Management and
natali 33 [55]

Answer:

a)\chi^2 = \frac{(40-35)^2}{35}+\frac{(35-40)^2}{40}+\frac{(25-25)^2}{25}+\frac{(25-24.5)^2}{24.5}+\frac{(35-28)^2}{28}+\frac{(25-17.5)^2}{17.5}+\frac{(5-10.5)^2}{10.5}+\frac{(10-12)^2}{12}+\frac{(15-7.5)^2}{7.5} =17.03

p_v = P(\chi^2_{4} >17.03)=0.0019

And we can find the p value using the following excel code:

"=1-CHISQ.DIST(17.03,4,TRUE)"

Since the p value is lower than the significance level we can reject the null hypothesis at 5% of significance, and we can conclude that we have association or dependence between the two variables.

b)

P(E|Ex)= P(EΛEx )/ P(Ex) = (40/215)/ (70/215)= 40/70=0.5714

P(E|Gx)= P(EΛGx )/ P(Gx) = (35/215)/ (80/215)= 35/80=0.4375

P(E|Fx)= P(EΛFx )/ P(Fx) = (25/215)/ (50/215)= 25/50=0.5

P(G|Ex)= P(GΛEx )/ P(Ex) = (25/215)/ (70/215)= 25/70=0.357

P(G|Gx)= P(GΛGx )/ P(Gx) = (35/215)/ (80/215)= 35/80=0.4375

P(G|Fx)= P(GΛFx )/ P(Fx) = (10/215)/ (50/215)= 10/50=0.2

P(F|Ex)= P(FΛEx )/ P(Ex) = (5/215)/ (70/215)= 5/70=0.0714

P(F|Gx)= P(FΛGx )/ P(Gx) = (10/215)/ (80/215)= 10/80=0.125

P(F|Fx)= P(FΛFx )/ P(Fx) = (15/215)/ (50/215)= 15/50=0.3

And that's what we see here almost all the conditional probabilities are higher than 0.2 so then the conclusion of dependence between the two variables makes sense.

Step-by-step explanation:

A chi-square goodness of fit test "determines if a sample data matches a population".

A chi-square test for independence "compares two variables in a contingency table to see if they are related. In a more general sense, it tests to see whether distributions of categorical variables differ from each another".

Assume the following dataset:

Quality management        Excellent      Good     Fair    Total

Excellent                                40                35         25       100

Good                                      25                35         10         70

Fair                                         5                   10          15        30

Total                                       70                 80         50       200

Part a

We need to conduct a chi square test in order to check the following hypothesis:

H0: There is independence between the two categorical variables

H1: There is association between the two categorical variables

The level of significance assumed for this case is \alpha=0.05

The statistic to check the hypothesis is given by:

\chi^2 = \sum_{i=1}^n \frac{(O_i -E_i)^2}{E_i}

The table given represent the observed values, we just need to calculate the expected values with the following formula E_i = \frac{total col * total row}{grand total}

And the calculations are given by:

E_{1} =\frac{70*100}{200}=35

E_{2} =\frac{80*100}{200}=40

E_{3} =\frac{50*100}{200}=25

E_{4} =\frac{70*70}{200}=24.5

E_{5} =\frac{80*70}{200}=28

E_{6} =\frac{50*70}{200}=17.5

E_{7} =\frac{70*30}{200}=10.5

E_{8} =\frac{80*30}{200}=12

E_{9} =\frac{50*30}{200}=7.5

And the expected values are given by:

Quality management        Excellent      Good     Fair       Total

Excellent                                35              40          25         100

Good                                      24.5           28          17.5        85

Fair                                         10.5            12           7.5         30

Total                                       70                 80         65        215

And now we can calculate the statistic:

\chi^2 = \frac{(40-35)^2}{35}+\frac{(35-40)^2}{40}+\frac{(25-25)^2}{25}+\frac{(25-24.5)^2}{24.5}+\frac{(35-28)^2}{28}+\frac{(25-17.5)^2}{17.5}+\frac{(5-10.5)^2}{10.5}+\frac{(10-12)^2}{12}+\frac{(15-7.5)^2}{7.5} =17.03

Now we can calculate the degrees of freedom for the statistic given by:

df=(rows-1)(cols-1)=(3-1)(3-1)=4

And we can calculate the p value given by:

p_v = P(\chi^2_{4} >17.03)=0.0019

And we can find the p value using the following excel code:

"=1-CHISQ.DIST(17.03,4,TRUE)"

Since the p value is lower than the significance level we can reject the null hypothesis at 5% of significance, and we can conclude that we have association or dependence between the two variables.

Part b

We can find the probabilities that Quality of Management and the Reputation of the Company would be the same like this:

Let's define some notation first.

E= Quality Management excellent     Ex=Reputation of company excellent

G= Quality Management good     Gx=Reputation of company good

F= Quality Management fait     Ex=Reputation of company fair

P(EΛ Ex) =40/215=0.186

P(GΛ Gx) =35/215=0.163

P(FΛ Fx) =15/215=0.0697

If we have dependence then the conditional probabilities would be higher values.

P(E|Ex)= P(EΛEx )/ P(Ex) = (40/215)/ (70/215)= 40/70=0.5714

P(E|Gx)= P(EΛGx )/ P(Gx) = (35/215)/ (80/215)= 35/80=0.4375

P(E|Fx)= P(EΛFx )/ P(Fx) = (25/215)/ (50/215)= 25/50=0.5

P(G|Ex)= P(GΛEx )/ P(Ex) = (25/215)/ (70/215)= 25/70=0.357

P(G|Gx)= P(GΛGx )/ P(Gx) = (35/215)/ (80/215)= 35/80=0.4375

P(G|Fx)= P(GΛFx )/ P(Fx) = (10/215)/ (50/215)= 10/50=0.2

P(F|Ex)= P(FΛEx )/ P(Ex) = (5/215)/ (70/215)= 5/70=0.0714

P(F|Gx)= P(FΛGx )/ P(Gx) = (10/215)/ (80/215)= 10/80=0.125

P(F|Fx)= P(FΛFx )/ P(Fx) = (15/215)/ (50/215)= 15/50=0.3

And that's what we see here almost all the conditional probabilities are higher than 0.2 so then the conclusion of dependence between the two variables makes sense.

7 0
3 years ago
The top of the desk is shaped like a trapezoid the bases of the trapezoid are 26.5 and 30 cm long the area of the desk is 791 CM
kotegsom [21]

Answer:

28 cm

Step-by-step explanation:

Given that :

Area = 791 cm

Base, b1 = 26.5 cm

Base, b2 = 30 cm

Area, A of trapezoid :

A = 1/2 (a + b) h

Where a and b are the bases ;

791 = 1/2(26.5 + 30)h

791 = 0.5(56.5)h

791 = 28.25h

h = 791 / 28.25

h = 28 cm

5 0
3 years ago
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