How many square feet of outdoor carpet for this hole

Mathematics

1 answer:

nevsk [136]3 years ago

8 0

Answer: 30

Step-by-step explanation:

2 x 5 = 10

2 x 6 = 12

2 x 4 = 8

10 + 12 + 8 = 30

You might be interested in

Because triangle XYZ is a right triangle, the side lengths must satisfy the Pythagorean theorem, a2 + b2 = c2, which in this iso

abruzzese [7]

Complete Question

Because triangle XYZ is a right triangle, the side lengths must satisfy the Pythagorean theorem, a² + b² = c², which in this isosceles triangle becomes a² + a² = c². By combining like terms, 2a² = c². Which final step will prove that the length of the hypotenuse, c, is StartRoot 2 EndRoot times the length of each leg?

a) substitute values for a and c into the original pythagorean theorem equation.

b) divide both sides of the equation by two, then determine the principal square root of both sides of the equation.

c) determine the principal square root of both sides of the equation.

d) divide both sides of the equation by 2.

Answer:

c) determine the principal square root of both sides of the equation.

Step-by-step explanation:

Pythagoras Theorem for a right angled triangles states that:

a²+ b²= c²

But for an Isosceles Triangle, where two sides of the triangle are equal, we have:

a²+ a² = c²

By combining like terms

2a² = c²

We square root both sides of the equation.

√2a² = √c

√2a² = c

The final step will prove that the length of the hypotenuse, c, is StartRoot 2 EndRoot times the length of each leg = √2a² = c is Option c.

4 0

3 years ago

Read 2 more answers

3.) 4(m + 5) + 42, (m = -2)

SpyIntel [72]

The answer would be 54 since m=-2

Step one: 4(-2+5)+42
Step two: (-8+20)+42=54

4 0

3 years ago

Read 2 more answers

Part A - Construct a circle of any radius, and draw a chord on it. The construct the radius of the circle that bisects the chord

Julli [10]

Answer:

It can be concluded that the intersection of a chord and the radius that bisects it is at right angle. The two are perpendicular.

Step-by-step explanation:

i. Construct the required circle of any radius as given in the question, then locate the chord. A chord joins two points on the circumference of a circle, but not passing through its center.

ii. Construct the radius to bisect the chord, dividing it into two equal parts.

Then it would be observed that the intersection of a chord and the radius that bisects it is at right angle. Thus, the chord and radius are are perpendicular to each other.

The construction to the question is herewith attached to this answer for more clarifications.