The approximate molar mass of lauryl alcohol is 183 g/mol.
As per Raoult's law:

Tb = the freezing point of benzene (5.5oC), Ts = the freezing point of the solution, K = the cryoscopic constant (5.12 K*kg/mol for benzene), and Cm = the molality of the solution.
/M
=
where ml is the mass of lauryl alcohol and ms is the mass of the solvent.
=K
/M
Therefore, M=
=
=183 g/mol.
<h3>Lauryl alcohol </h3>
An organic substance called lauryl alcohol is created industrially from coconut or palm kernel oil. It is an alcoholic fat. The use of sodium lauryl sulfate and other sulfate esters of lauryl alcohol as surfactants is extremely common. In shampoos, sodium laureth sulfate, ammonium laureth sulfate, and sodium lauryl sulfate are all utilized. Lauryl alcohol has a floral scent and is flavorless and colorless. In addition to being a flavor-enhancing food additive, lauryl alcohol is also used to create medicines, lubricating lubricants, surfactants, and monolithic polymers. Lauryl alcohol is a kind of emollient used in cosmetics. Lauryl alcohol, a significant scent, and 1-bromododecane, an alkylating agent used to increase the lipophilicity of organic molecules, are both precursors to Lauryl alcohol.
A solution of 5. 00 g of lauryl alcohol in 0. 100 kg of benzene freezes at 4. 1°c. what is the approximate molar mass of lauryl alcohol?
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Answer:
Mechanical weathering will cause wearing down of rocks.
Explanation:
All the other choices aren't suitable for a dry climate where sand storms occur.
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No, the correct answer is B. Physical change because the identity of the substance does not change.
For example, if you take a piece of paper and tear it in half you actually changed its property because now those pieces of paper have half the weight and and size that they did before you did anything. Now you know its a physical change because its still paper all you have done is change the physical appearance.
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We can calculate for temperature by assuming the equation
for ideal gas law:
P V = n R T
Where,
P = pressure = 1.80 atm
V = volume = 18.2 L
n = number of moles = 1.20 moles
R = gas constant = 0.08205746 L atm / mol K
Substituting to the given equation:
T = P V / n R
T = (1.8 atm * 18.2 L) / (1.2 moles * 0.08205746 L atm /
mol K)
T = 332.70 K
We can convert K unit to ˚C unit by subtracting 273.15
to Kelvin, therefore
T = 59.55 ˚<span>C</span>