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LiRa [457]
3 years ago
9

What is the empirical formula for glucose A) B) C) D)

Chemistry
2 answers:
Schach [20]3 years ago
6 0
C6h12O6 ( the D one it’s the correct one)
pshichka [43]3 years ago
4 0
The Answer is A CH2O

The molecular formula for glucose is C6H12O6. The subscripts represent a multiple of an empirical formula. To determine the empirical formula, divide the subscripts by the GCF of 6 which gives CH2O.
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Answer:

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3 years ago
Naturally occurring element X exists in three isotopic forms: X-28 (27.979 amu, 92.21% abundance), X-29 (28.976 amu 4.70% abunda
bezimeni [28]

<u>Answer:</u> The average atomic mass of X is 28.09 amu

<u>Explanation:</u>

Average atomic mass of an element is defined as the sum of masses of each isotope each multiplied by their natural fractional abundance.

Formula used to calculate average atomic mass follows:

\text{Average atomic mass }=\sum_{i=1}^n\text{(Atomic mass of an isotopes)}_i\times \text{(Fractional abundance})_i .....(1)

  • <u>For isotope 1:</u>

Mass of isotope 1 = 27.979 amu

Percentage abundance of isotope 1 = 92.21 %

Fractional abundance of isotope 1 = 0.9212

  • <u>For isotope 2:</u>

Mass of isotope 2 = 28.976 amu

Percentage abundance of isotope 2 = 4.70 %

Fractional abundance of isotope 2 = 0.0470

  • <u>For isotope 3:</u>

Mass of isotope 3 = 29.974 amu

Percentage abundance of isotope 3 = 3.09 %

Fractional abundance of isotope 3 = 0.0309

Putting values in equation 1, we get:

\text{Average atomic mass of X}=[(27.979\times 0.9212)+(28.976\times 0.0470)+(29.974\times 0.0309)]

\text{Average atomic mass of X}=28.09amu

Hence, the average atomic mass of X is 28.09 amu

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3 years ago
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AnnyKZ [126]
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Question 13 (1 point)
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3 years ago
from the balanced equation we see that h20 is 1 to 1 mole ratio the number of moles of acid and base. What is the number of mole
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Number of moles = concentration in mol/L × volume in L

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Volume = 49.8 mL = 49.8/1000 = 0.0498 L

Number of moles = 1×0.0498 = 0.0498 mol

5 0
4 years ago
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