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Butoxors [25]
4 years ago
8

In this lab, you are to carry out the formation of a Grignard reagent from 1-bromo-benzene andits subsequent reaction with solid

carbon dioxide (CO2) followed by acidic workup (using HCl asthe acid). Write the overall reaction and product(s) that you expect.
Chemistry
1 answer:
yan [13]4 years ago
5 0

Answer:

(A). C6H5Br + Mg(in ether) -----------> C6H5MgBr.

(B). C6H5MgBr + O = C = O -----------> C6H5-COO^- Mg^+ Br.

(C). C6H5-COO^- Mg^+ Br + HCl --------> C6H5-COOH + Mg^+Br(OH).

PRODUCTS=> C6H5-COOH and Mg^+Br(OH).

Explanation:

A Grignard reagent is a reagent that/which is an organometallic compound that is R -Mg- X. The R = alkyl, vinyl or allyl and the X = halogens.

It must be noted that an important reaction of Grignard reagent is its reaction with compounds containing the Carbonyl that is -CO functional group and this kind of Reaction is known as a Grignard Reaction.

So, in this question we are told that;

=> "1-bromo-benzene andits subsequent reaction with solid carbon dioxide (CO2) followed by acidic workup (using HCl asthe acid). "

Thus;

(A). C6H5Br + Mg(in ether) -----------> C6H5MgBr.

(B). C6H5MgBr + O = C = O -----------> C6H5-COO^- Mg^+ Br.

(C). C6H5-COO^- Mg^+ Br + HCl --------> C6H5-COOH + Mg^+Br(OH).

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aleksandrvk [35]

The answer was 25

Do according to bodmas rule

6 0
3 years ago
How many grams of silver bromide are produced when 505 grams of cobalt (III) bromide reacts completely in the following equation
DedPeter [7]
Mass = 473.2 g
Explanation:
Given data:
Mass of cobalt(III) nitrate = 206 g
Mass of silver bromide produced = ?
Solution:
Chemical equation:
CoBr₃ + 3AgNO₃ → 3AgBr + Co(NO₃)₃
Number of moles of cobalt(III) nitrate:
Number of moles = mass/ molar mass
Number of moles = 206 g/ 245 g/mol
Number of moles = 0.84 mol
Now we will compare the moles of cobalt(III) nitrate with silver bromide.
7 0
3 years ago
How many oxygen atoms are present in 4.28 g of LiBroz sample?
Dafna11 [192]

Answer:

0.43×10²³ atoms

Explanation:

Given data:

Mass of LiBrO₂ = 4.28 g

Number of atoms of oxygen = ?

Solution:

Number of moles = mass/molar mass

Number of moles = 4.28 g/ 118.84 g/mol

Number of moles = 0.036 mol

We can see 1 mole of LiBrO₂ contain 2 mole of oxygen atm.

0.036 mol × 2 = 0.072 mol

1 mole contain 6.022×10²³ atoms

0.072 mol × 6.022×10²³ atoms / 1mol

0.43×10²³ atoms

3 0
3 years ago
OK SO HERES HOW ITS GONNA GO. IMA ASK YOU GUYS ONE MORE TIME BC THIS IS LIKE THE 3RD TIME IVE WAISTED MY POINTS IN THE SAME QUES
Ne4ueva [31]

Answer:

Electronic Configuration of calcium ion: Ca²⁺

1s², 2s², 2p⁶, 3s², 3p⁶

Explanation:

Calcium belong to group IIA and known as alkaline earth metals.

  • it have two electrons in outer most orbital.
  • these outer two electrons are involve in bonding
  • calcium lose these two electron and form cation
  • cation have 2+ charge
  • calcium have total twenty electrons

Electronic Configuration of calcium atom: ²⁰Ca

1s², 2s², 2p⁶, 3s², 3p⁶, 4s²

When calcium ion is form it loses two electron and have 2+ charge on it.

and have total of 18 electrons

So,

Electronic Configuration of calcium ion: Ca²⁺

the last filled orbital will be 3p⁶

1s², 2s², 2p⁶, 3s², 3p⁶

4 0
4 years ago
Solutions of hydrochloric acid caused the light bulb to glow brighter than solutions of acetic acid. how do you account for the
maksim [4K]
<span>The primary difference between hydrochloric acid and acetic acid is that hydrochloric acid undergoes a complete ionization, whereas acetic acid does not. This is why a light bulb will burn brighter in the solutions of hydrochloric acid, and also why hydrochloric acid is considered a strong acid, while acetic acid is considered a weak acid.</span>
7 0
3 years ago
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