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3 years ago

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The standard cell potential (e°cell) of the reaction below is -0.55 v. the value of δ g° for the reaction is ________ j/mol. i2

(s) + 2br- (aq) → 2i- (aq) + br2 (l)

1 answer:

den301095 [7]3 years ago

5 0

Check the attached file for the answer.

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What is an ideal gas? how many ideal gases are there in the universe?

tiny-mole [99]

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Not exactly sure about the amount...
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Which information is revealed in a chemical formula?

wariber [46]

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A 19-g piece of metal absorbs 186.75 joules of heat energy, and its temperature changes from 35°C to 175°C. Calculate the specif

slavikrds [6]

Answer:

0.0702J/g°C the specific heat capacity of the metal.

Explanation:m

$Q=m\times c\times \Delta T=m\times c\times (T_{2}-T_{1})$

where,

Q = heat absorbed by metal = 186.75 J

$m_1$ = Mass of metal= 19 g

$T_1$ = Initial temperature of metal = $35^oC$

$T_2$ =Final temperature of metal = $175^oC$

$c$ = specific heat of metal= ?

$186.75 J=19 g\times c\times (175^oC-35^oC)$

$c=\frac{186.75 J}{19 g\times (175^oC-35^oC)}$

$c=0.0702J/g^oC$

0.0702J/g°C the specific heat capacity of the metal.

6 0

3 years ago

You are asked to prepare 500. mL 0.150 M acetate buffer at pH 5.10 using only pure acetic acid ( MW = 60.05 g/mol, p K a = 4.76

Amanda [17]

Answer:

4.504g of acetic acid

Explanation:

The acetic acid in reaction with NaOH produce acetate ion, thus:

CH₃COOH + NaOH → CH₃COO⁻ + H₂O + Na⁺

<em>That means the moles of acetate buffer comes, in the first, from the acetic acid</em>

As you need 500mL (0,500L) of a 0.150M acetate buffer, moles are:

0.500L × (0.150mol / 1L) = <em>0.075 moles of acetate</em>. That is:

0.075mol = [CH₃COO⁻] + [CH₃COOH]

Thus, grams of acetic acid you need to prepare the buffer are:

0.075 moles acetic acid × (60.05g / 1mol) = <em>4.504g of acetic acid</em>

6 0

3 years ago

What mass of magnesium oxide is formed when 48.62g of magnesium is reacted with excess oxygen?

marin [14]

Answer: -

81.03 g magnesium oxide is formed when 48.62g of magnesium is reacted with excess oxygen

Explanation: -

Atomic mass of Mg = 24 g

Molar mass of MgO = 24 x 1 + 16 x 1

= 40 g

The balanced chemical equation for this reaction is

2 Mg + O₂ → 2MgO

From the balanced chemical equation we see

2 mol of Mg gives 2 mol of MgO.

2 x 24 g of Mg gives 2 x 40g of MgO.

48.62 g of Mg gives $\frac{2 x 40 g MgO}{2 x 24 g Mg}$ x Mg

= 81.03g of MgO

5 0

3 years ago