Question

The football players collide head-on in midair while trying to catch a thrown football. The first player is 95.0 kg and has an initial velocity of 6.00 m/s, while the second player is 115 kg and has an initial velocity of –3.50 m/s. What is their velocity just after impact if they cling together?

Answer 1

Answer:

$v=0.8m/s$

Explanation:

To solve the problem, we can use collisions theory from classical physics

If we analyze the players before and after the collision we got:

$p_{1}=p_{2}$

Since the cling together

$m_{1}v_{1}+m_{2}v_{2}=(m_{1}+m_{2})v$

From the exercise we know that the first player is 95.0 kg and has an initial velocity of 6.00 m/s, while the second player is 115 kg and has an initial velocity of –3.50 m/s.

$v=\frac{m_{1}v_{1}+m_{2}v_{2}}{(m_{1}+m_{2})}=\frac{(95kg)(6m/s)+(115kg)(-3.5m/s)}{(95+115)kg}$

$v=0.797m/s=0.8m/s$