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3 years ago

What are the variables of Boyle's law?

Physics

1 answer:

vesna_86 [32]3 years ago

3 0

Answer: pressure and volume

Explanation:

Boyle's law states that the volume of a fixed mass of gas is inversely proportional to the pressure of the gas provided temperature is kept constant.

Mathematically, Boyle's law can be explained as: PV = k,

where P is pressure

V is volume, and

k is a constant.

So, increase in the pressure of a gas leads to decrease in its volume and vice versa.

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3 years ago

The atmospheric pressure on a mountain is 550 mmHg and 1 atm is equal to 760 mmHg. What is the pressure in atm? Give your answer

Svetradugi [14.3K]

Answer:

0.72 atm

Explanation:

Given that the atmospheric pressure on a mountain is 550 mmHg.

Where 1 atm is equal to 760 mmHg.

To Convert millimetre mercury (mmHg) into atmospheric pressure units (atm) , divide the magnitude of pressure by 760. That is,

Pressure = 550/760

Pressure = 0.724 atm

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3 years ago

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2 years ago

A 7.00 g bullet, when fired from a gun into a 1.10 kg block of wood held in a vise, penetrates the block to a depth of 9.60 cm.

kvasek [131]

Explanation:

The given data is as follows.

Mass of bullet 1, $m_{b}$ = 7 g = $7 \times 10^{-3} kg$

Mass of block of wood, M = 1.10 kg

Bullet penetrates to depth, $x_{1}$ = 9.60 cm = $9.60 \times 10^{-2} m$

Mass of bullet 2, $m_{B}$ = 7 g = $7 \times 10^{-3} kg$

Velocity of bullet = v

Let us assume that depth of penetration of the bullet is $x_{2}$ .

According to the law of conservation of energy,

Kinetic energy = Potential energy

Kinetic energy = $\frac{1}{2}mv^{2}$

and, Potential energy = mgh

so, for bullet 1

$\frac{1}{2}m_{b}v^{2}_{1} = m_{b}gx_{1}$ .......... (1)

For bullet 2,

Kinetic energy of bullet 1 - kinetic energy of bullet 2 = Potential energy

$\frac{1}{2}m_{b}v^{2}_{1} - \frac{1}{2}(M + m_{b} + m_{B})v^{2}_{2} = m_{b}gx_{2}$

Using equation (1), we get

$m_{b}gx_{1} - \frac{1}{2}(M + m_{b} + m_{B})v^{2}_{2} = m_{b}gx_{2}$

$x_{2} = \frac{x_{1}(M + m_{b})}{(M + m_{b} + m_{B})}$

Putting the given values into the above formula as follows.

$x_{2} = \frac{x_{1}(M + m_{b})}{(M + m_{b} + m_{B})}$

= $\frac{9.60 \times 10^{-2}(1.10 + 7 \times 10^{-3})}{(1.10 + 7 \times 10^{-3} + 7 \times 10^{-3})}$

= 0.0953 m

or, = 9.53 cm (as 1 m = 100 cm)

Thus, we can conclude that the bullet will penetrate at a depth of 9.53 cm.

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3 years ago