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Alekssandra [29.7K]
3 years ago
6

Now move the center of rotation, R, to a different position on the coordinate plane.

Mathematics
1 answer:
Scilla [17]3 years ago
4 0

Answer: If the center of rotation is changed, the pentagon maps back onto itself only one time, when the value of a is 360 degrees that is, when the pentagon completes a full rotation.  (just a heads up if your going to copy and paste, change it up a bit because this is word for word :) hope it helped!)

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The position equation for a particle is s of t equals the square root of the quantity t cubed plus 1 where s is measured in feet
vladimir1956 [14]
\bf s(t)=\sqrt{t^3+1}
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\cfrac{ds}{dt}=\cfrac{1}{2}(t^3+1)^{-\frac{1}{2}}\cdot 3t^2\implies \boxed{\cfrac{ds}{dt}=\cfrac{3t^2}{2\sqrt{t^3+1}}}\leftarrow v(t)
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\cfrac{d^2s}{dt^2}=\cfrac{6t(2\sqrt{t^3+1})-3t^2\left( \frac{3t^2}{\sqrt{t^3+1}} \right)}{(2\sqrt{t^3+1})^2}\implies 
\cfrac{d^2s}{dt^2}=\cfrac{ \frac{6t(2\sqrt{t^3+1})-1}{\sqrt{t^3+1}} }{4(t^3+1)}

\bf \cfrac{d^2s}{dt^2}=\cfrac{6t[2(t^3+1)]-1}{4(t^3+1)\sqrt{t^3+1}}\implies 
\boxed{\cfrac{d^2s}{dt^2}=\cfrac{12t^4+12t-1}{4t^3+4\sqrt{t^3+1}}}\leftarrow a(t)\\\\
-------------------------------\\\\a(2)=\cfrac{215~ft^2}{44~sec}
8 0
3 years ago
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The graphs of f(x) and g(x) are shown below. On a coordinate plane, a straight line with negative a slope represents f (x) = neg
juin [17]
Graph it to a then to b then to c and you will have your answer sikew
6 1
2 years ago
Uhh I got this answer wrong my brain wasn’t working so I guessed and picked wet and salty
Dahasolnce [82]

Answer:

dry and hot

Step-by-step explanation:

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4 0
3 years ago
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I need help with this
Monica [59]

Using derivatives, it is found that regarding the tangent line to the function, we have that:

  • The slope is of 962.
  • The equation of the line is y = 962x - 5119.

<h3>What is a linear function?</h3>

A linear function is modeled by:

y = mx + b

In which:

  • m is the slope, which is the rate of change, that is, by how much y changes when x changes by 1.
  • b is the y-intercept, which is the value of y when x = 0, and can also be interpreted as the initial value of the function.

The slope of the line tangent to a function f(x) at x = x' is given by f'(x'). In this problem, the function is given by:

f(x) = 5x³ + 2x + 1.

The derivative is given by:

f'(x) = 15x² + 2.

Hence the slope at x = 8 is:

m = f'(8) = 15(8)² + 2 = 962.

The line goes through the point (8,f(8)), hence:

f(8) = 5(8)³ + 2(8) + 1 = 2577.

Hence:

y = 962x + b

2577 = 962(8) + b

b = -5119.

Hence the equation is:

y = 962x - 5119.

More can be learned about tangent lines at brainly.com/question/8174665

#SPJ1

7 0
2 years ago
Solve the system by elimination
andreev551 [17]
The answer is x=5 and y=-2

3 0
3 years ago
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