Which of the three equations have infinitely many solutions?

Mathematics

2 answers:

mina [271]3 years ago

6 0

Answer:

I need to know the questions luv.

Step-by-step explanation:

mr Goodwill [35]3 years ago

3 0

Answer:

Solving the three equations in part A showed that two equations have one solution and one equation has no solution. So, no equations have infinitely many solutions.

Step-by-step explanation:

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Can I get help plzzz

Katarina [22]

Answer:

Step-by-step explanation:

N = (-1, -1)

-1 + 1 = 0

-1 - 1 = -2

So the new coordinates are (0,-2), same with the other coordinates.

7 0

3 years ago

Find the 90% confidence interval for the population standard deviation given the following.

lions [1.4K]

Answer:

b. 2.01 < σ < 2.81

Step-by-step explanation:

The 90% confidence interval for the population standard deviation is calculated as:

$\sqrt{\frac{(n-1)*s^{2} }{X^2_{\alpha/2 } } }$ < σ < $\sqrt{\frac{(n-1)*s^{2} }{X^2_{1-\alpha/2 } } }$

Where n is equal to 51, s is equal to 2.34, $\alpha$ is 10%, $X^{2} _{\alpha /2}$ is the value for the Chi squared distribution with n-1 degrees of freedom that has a probability of $\alpha /2$ in the right tail and $X^{2} _{1-\alpha /2}$ is the value for the Chi squared distribution with n-1 degrees of freedom that has a probability of $1-\alpha /2$ in the right tail.

So, replacing n by 51, s by 2.34, $X^{2} _{\alpha /2}$ by 67.50 and $X^{2} _{1-\alpha /2}$ by 34.76, we get that the The 90% confidence interval is equal to:

$\sqrt{\frac{(51-1)*2.34^{2} }{67.50} } }$ < σ < $\sqrt{\frac{(51-1)*2.34^{2} }{34.76} } }$