All categories

4 years ago

Luminous objects such as flashlights emit light that we can see. How do we see an object that isn’t luminous?

2 answers:

5 0

I think the correct answer from the choices listed above is the second option. <span>In order for us to see an </span>object<span> that is </span>non-luminous<span>, it must reflect some of the light it receives from a </span>luminous<span> source, such as the Sun. Hope this answers the question. Have a nice day.</span>

Sonja [21]4 years ago

3 0

The correct answer is option B

The objects that allows the light to radiated from its body is called as luminous object. Whenever any light ray falls on any object it gets reflected back to the to the eyes of the observer. The light falls off the object that is not luminous and gets reflected back into the eyes of the observer. This makes the object visible to the people.

You might be interested in

Ms. Tierney arrives in the Emergency Department with a burn that extends throughout the dermis and epidermis. It is hard, dry, a

Helen [10]

Third degree or full thickness

7 0

2 years ago

1. What system's organs dominate the abdominal cavity?

irakobra [83]

Answer:

Pancreas, Spleen , Kidneys

Explanation:

I think

8 0

4 years ago

Which has more potential energy (or the same?), Joe Arva sitting in a tree, or the apple next to him?

Tpy6a [65]

Joe arva as he has more mass than the apple.

3 0

4 years ago

According to the U.S. Department of Energy, a typical home in the United States uses approximately 900 kWh of electricity per mo

guapka [62]

Based on the energy generated by the power plant annually, the number of households the plant can support:

if energy usage is 10,800 kWh/year = 365000 households
if energy usage is 24000 kWh/year = 164250 households

<h3>What is electrical energy?</h3>

Energy is energy that is due to movement of electrically charged particles.

Electrical energy is used in homes for many purposes.

Electrical energy is sold in units of kWh.

Data provided:

Capacity of power plant = 500 MW

Capacity factor = 0.9

Average annual household energy usage = 10,800 kWh/year

Energy generated in a year = 24 × 365 × 0.9 × 500 MW = 3,942,000 MWh/year

3,942,000 kWh/year = 3,942,000,000 kWh/year.

Number of households the power plant can support = 3,942,000,000 kWh/10800 = 365000 households

Number of households the power plant can support is 365000 households

If monthly electricity usage increases to 1,200 kWh

In a year, energy usage = 1200 × 12 = 24,000 kWh/ year

Number of households the plant can support = 3,942,000,000 kWh/24,000 = 164250 households

Therefore, based on the energy generated by the power plant annually, the number of households the plant can support:

if energy usage is 10,800 kWh/year = 365000 households
if energy usage is 24000 kWh/year = 164250 households

Learn more about about electrical energy at: brainly.com/question/25475663

8 0

3 years ago

Use an examples to distinguish dominant and recessive phenotypes.

steposvetlana [31]

Think recessive phenotypes as paper and dominant phenotypes as teared paper. Once paper is teared, it can't be fixed. Not even tape. It'll just leave that mess exposed. Same with dominant phenotypes. It just takes one dominant trait to change the looks of future offspring.

If you don't tear the paper, everything is fine. Same with recessive phenotypes. As long as there's no contact with any dominant phenotypes, the looks of future offspring will change.

6 0

3 years ago