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BigorU [14]
3 years ago
7

When x = 8, y=10 , find y when x = 64

Mathematics
1 answer:
worty [1.4K]3 years ago
4 0

Answer:

When x = 64, y = 80.

Step-by-step explanation:

Since the origanal value was 8 and now it´s 64, lets divide to see how much was multiplied. Then lets multipliy it with that number.

64 / 8 = 8

Soo..8 x 10 = 80.

When x = 64, y = 80.

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baherus [9]
If m1 and m2 are the slopes of each line, for them to be perpendicular you gotta solve
m1 * m2 = -1
4 0
3 years ago
What are the solutions to
Svetllana [295]

Answer:

B and F

Step-by-step explanation:

Given

x² + 4x + 4 = 12 ( subtract 4 from both sides )

x² + 4x = 8

Using the method of completing the square to solve for x

add ( half the coefficient of the x- term )² to both sides

x² + 2(2)x + 4 = 8 + 4, that is

(x + 2)² = 12 ( take the square root of both sides )

x + 2 = ± \sqrt{12} ( subtract 2 from both sides )

x = ± \sqrt{12} - 2

  = ± 2\sqrt{3} - 2

Hence

x = 2\sqrt{3} - 2 → B

x = - 2\sqrt{3} - 2 → F

4 0
3 years ago
Find the following when a = -1, b = 2, c = -1/4<br> (4b - 3)/(2a) -1
Katena32 [7]
We substitute the given into the equation
given: a=-1, b=2, c=\frac{-1}{4}
=(\frac{4b-3}{2a}-1
=\frac{4(2)-3}{2(-1)}-1
=\frac{8-3}{-2}-1
=\frac{5}{-2}-1
to continue, we can either find a common denominator or change the fraction to decimal.
Fraction to Decimal:
\frac{5}{-2}=-2.5
Equation=-2.5-1=-3.5
OR Common Denominator:
=\frac{5}{-2}\frac{-1}{1}×\frac{-2}{-2}         (denominator should be -2=common)
=\frac{5}{-2}+\frac{2}{-2}
=\frac{7}{-2}
which also = to -3.5
3 0
3 years ago
How do you solve 3/4 (5+x) + 4 = 3x + 1? Thanks:)
elena-s [515]

\dfrac{3}{4}(5+x)+4=3x+1\ \ \ \ |\cdot4\\\\3(5+x)+16=12x+4\ \ \ |\text{use distributive property}\\\\(3)(5)+(3)(x)+16=12x+4\\\\15+3x+16=12x+4\\\\31+3x=12x+4\ \ \ \ |-31\\\\3x=12x-27\ \ \ \ |-12x\\\\-9x=-27\ \ \ \ |:(-9)\\\\\boxed{x=3}

3 0
3 years ago
What is the equation of a quadratic function P with rational coefficients that
Phoenix [80]

Answer:

P(x) = x^2-6x+58

Step-by-step explanation:

Quadratic function is function of the form P(x)=ax^2+bx+c where a, b and c are real numbers and a\neq 0

A number is said to be a rational number if it can be written in the form \frac{u}{v} where u and v are integers and v\neq 0.

A number is said to be a complex number if it can be written in the form u+iv where u and v are real numbers.

A number 'a' is said to be a zero of a function P(x) if P(a)=0

We know that if zero of a fraction is of form u+iv then its other zero is u-iv.

As 3+7i is a zero of the function, 3-7i is also its zero.

So, given equation is \left ( x-(3-7i) \right )\left ( x-(3+7i) \right )

P(x)=\left ( x-(3-7i) \right )\left ( x-(3+7i) \right )\\=x^2-x(3+7i)-x(3-7i)+(3-7i)(3+7i)\\=x^2-3x-7ix-3x+7ix+9+49\\=x^2-6x+58

4 0
3 years ago
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