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butalik [34]
4 years ago
13

Compare the values of the underlined digits

Mathematics
2 answers:
BaLLatris [955]4 years ago
5 0
The 3 in 6,300 is 10 times greater the 3 in 530 The 4 in 47,163 is 10 times greater than the 4 in 34,258
VikaD [51]4 years ago
3 0

Answer:

The value of 3 in 6,300 is 10 times the value of 3 in 530.

The vale of 4 in 47163 is 10 times of the vale of 4 in 34258 .

Step-by-step explanation:

Given  : (1 )6,300 and 530  

(2) 34.258 and 47,163

To find : Compare the values of the underline digits.  

Solution : We have given 6,300 and 530

In 6,300  

Value of 3 in 6,300 is 3 hundred = 300.

In 530

Value of 3 in 530 is 3 tens = 30.

3 hundred is 10 times of thirty

 The value of 3 in 6,300 is 10 times the value of 3 in 530.

Part 2)

In 3,4258

Value of 4 in 3,4258 is 4 thousand = 4000.

In 47,163

of 4 in 47,163 is 40 thousand = 40000.

The vale of 4 in 47163 is 10 times of the vale of 4 in 34258 .

Therefore, The value of 3 in 6,300 is 10 times the value of 3 in 530.

The vale of 4 in 47163 is 10 times of the vale of 4 in 34258 .

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What is the value of (4 minus 2) cubed minus 3 times 4?<br> Negative 20
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