ANYONE PLEASE HELP!!
1 answer:
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Start by stating the given info as mathematical expressions:
1. "<span>The width of a rectangle is 6 cm less than its length."
2. "I</span><span>ts perimeter is 80 cm."
Using the formula for perimeter (
) we can show:
.
We now have 2 equations in 2 unknowns and can solve by substitution:
</span>
The length is 23cm.
Having the length w can then find the width:
The width is 17cm.
And finally the area:
The area is
.
As a check we can use the known perimeter:
Checks true.
1. "<span>The width of a rectangle is 6 cm less than its length."
2. "I</span><span>ts perimeter is 80 cm."
Using the formula for perimeter (
We now have 2 equations in 2 unknowns and can solve by substitution:
</span>
The length is 23cm.
Having the length w can then find the width:
The width is 17cm.
And finally the area:
The area is
As a check we can use the known perimeter:
G `( x ) =
2 + k x = 0
k x = -2
k = -2: x = - 2 : 2/3 = - 2 * 3/2
k = - 3
Answer: for k= - 3, the function g ( x ) have a critical point at x = 2/3.
2 + k x = 0
k x = -2
k = -2: x = - 2 : 2/3 = - 2 * 3/2
k = - 3
Answer: for k= - 3, the function g ( x ) have a critical point at x = 2/3.