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Juliette [100K]
3 years ago
8

How many grams of sodium benzoate should be added to prepare the buffer? Neglect the small volume change that occurs when the so

dium benzoate is added.
Chemistry
1 answer:
expeople1 [14]3 years ago
3 0

Answer:

2.72 grams

Explanation:

Complete question is

You are asked to pre pare a pH = 4.00 buffer starting from 1.50 L of 0.0200 M solution of benzoic acid

(C6H5COOH)

and any amount you need of sodium benzoate

(C6H5COONa)

How many grams of sodium benzoate should be added to prepare the buffer? Neglect the small volume change that occurs when the sodium benzoate is added.

Solution

Given

pH of the buffer solution = 4

Concentration of C6H5COOH = 0.02 M

Volume of the buffer solution = 1.50 L

K_a value for benzoic acid is 6.3 * 10^ {-5}

Concentration of sodium benzoate

pH = - log Ka + log \frac{C6H5COONa}{C6H5COOH}

Substituting the given values we get

log \frac{C6H5COONa}{C6H5COOH}  = 4 + log (6.3 * 10^ {-5})\\log \frac{C6H5COONa}{C6H5COOH}  = -0.20\\\frac{C6H5COONa}{C6H5COOH} = 10^{-0.2}\\{C6H5COONa} = 10^{-0.2} * 0.02\\{C6H5COONa} =  0.63 * 0.02\\{C6H5COONa} =  0.0126 M

Number of moles in sodium benzoate

= 0.0126 * 1.5 \\= 0.0189 Mol

Mass of sodium benzoate

0.0189 mol * 144.147 \frac{g}{mol} \\= 2.72 g

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