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3 years ago

A gas occupies 12.3 liters at a temperature of 40.0k what is the volume when the temperature is increased to 60.0k

Chemistry

1 answer:

blagie [28]3 years ago

6 0

Answer:

18.45L

Explanation:

V1 = 12.3L

T1 = 40K

T2 = 60K

V2 = ?

This question involves the use of Charles law which states that the volume of a fixed mass of gas is directly proportional to its temperature provided that pressure remains constant.

Mathematically,

V = kT k = V/T

V1 / T1 = V2 / T2 = V3 / T3 =.......=Vn / Tn

V1 / T1 = V2 / T2

V2 = (V1 × T2) / T1

V2 = (12.3 × 60) / 40

V2 = 18.45L

The final volume of the gas is 18.45L

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3 years ago

A 15.0-L scuba diving tank contains a helium-oxygen (heliox) mixture made up of 23.0 g of He and 4.14 g of O2 at 298 K. Calculat

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Answer: The mole fraction of Helium is 0.978 and that of oxygen gas is 0.022

Explanation:

To calculate the number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$ .....(1)

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Putting values in equation 1, we get:

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For oxygen gas:

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Putting values in equation 1, we get:

$\text{Moles of oxygen gas}=\frac{4.14g}{32g/mol}=0.129mol$

Mole fraction of a substance is given by:

$\chi_A=\frac{n_A}{n_A+n_B}$

For helium:

Moles of helium = 5.75 moles

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Putting values in above equation, we get:

$\chi_{(He)}=\frac{5.75}{5.879}=0.978$

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4 years ago

The hydrogen gas formed in a chemical reaction is collected over water at 30.0 ∘c at a total pressure of 734 mmhg . part a what

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P Hydrogen = 734 mm Hg – 32 mm Hg = 702 mm Hg

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