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Vilka [71]
3 years ago
9

The value of the equilibrium constant K depends on: I. the initial concentrations of the reactants. II. the initial concentratio

ns of the products. III. the final concentrations of the reactants. IV. the final concentrations of the products.
Chemistry
1 answer:
Elden [556K]3 years ago
4 0

Answer:

None of these

Explanation:

For a reaction;

aA + bB ------>cC + dD

The equilibrium constant K is given as;

K = [C]^c [D]^d/[A]^a [B]^b

The equilibrium constant neither depends on the concentrations of the reactants nor on that of the products.

Let us recall that at equilibrium, the concentrations of reactants and products remain largely constant. This implies that, concentration of species do not appreciably change at equilibrium because the rates of forward and reverse reactions are equal.

Hence, the equilibrium constant neither depends on the initial/final concentrations of the reactants nor on the initial/final concentrations of the products.

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What type of rock is a obsidian , marble, and a conglomentary rock
laiz [17]

Hi There!

Obsidian - Igneous Rock

Marble - Metamorphic Rock

Conglomentary - Sedimentary Rock

Hope This Helps :)

6 0
4 years ago
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Some students were building models of solids, liquids, and gases by gluing plastic balls to a sheet of cardboard. which of their
JulsSmile [24]
Below picture contains the given models.

Answer:
            Option-B is the correct model.

Explanation:
                   Solid is a state of matter in which the particles are closely packed, has definite volume and shape. Like liquids they don't flow, either they occupy the volume of container as that occupied by both gases and liquids. The inter-molecular forces between solid particles are very strong as compared to liquids ans gases. So, the model B has a particles very closely packed to each other.

7 0
3 years ago
Write your question here (Keep it simple and clear to get the best answer) calculate the atomic weight of a metal when 125ml of
lana [24]

Answer:

The answer to your question is 24.32 g

Explanation:

Data

Atomic weight = ?

HCl volume = 125 ml

Molarity = 0.2

mass of metal = 0.304 g

Balanced chemical equation

                       M + 2HCl   ⇒  MCl₂  +  H₂

Process

1.- Calculate the moles of HCl

Molarity = moles / volume (L)

- Solve for moles

  moles = Molarity  x volume

  moles = 0.2 x 0.125

             = 0.025

2.- Calculate the moles of the Metal

                1 mol of M ----------------- 2 moles of HCl

                x                ----------------- 0.025 moles of HCl

                x = (0.025 x 1) / 2

                x = 0.0125 moles of HCl

3.- Calculate the atomic weight of the metal

                atomic weight ---------------- 1 mol

               0.304 g             ---------------0.0125 moles

               Atomic weight = (1 x 0.304) / 0.0125

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7 0
3 years ago
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How many Liters of a 4.5 M HCL solution can be prepared by using 250.0 mL of a 12.0 M HCl solution?
netineya [11]

Answer:

0.667 L

Explanation:

From the question given above, the following data were obtained:

Initial volume (V₁) = 250 mL

Initial concentration (C₁) = 12 M

Final concentration (C₂) = 4.5 M

Final volume (V₂) =?

The final volume of the solution can be obtained by using the dilution formula as illustrated below:

C₁V₁ = C₂V₂

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Divide both side by 4.5

V₂ = 3000 / 4.5

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How are Newton's three laws of motion related
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