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Vilka [71]
3 years ago
9

The value of the equilibrium constant K depends on: I. the initial concentrations of the reactants. II. the initial concentratio

ns of the products. III. the final concentrations of the reactants. IV. the final concentrations of the products.
Chemistry
1 answer:
Elden [556K]3 years ago
4 0

Answer:

None of these

Explanation:

For a reaction;

aA + bB ------>cC + dD

The equilibrium constant K is given as;

K = [C]^c [D]^d/[A]^a [B]^b

The equilibrium constant neither depends on the concentrations of the reactants nor on that of the products.

Let us recall that at equilibrium, the concentrations of reactants and products remain largely constant. This implies that, concentration of species do not appreciably change at equilibrium because the rates of forward and reverse reactions are equal.

Hence, the equilibrium constant neither depends on the initial/final concentrations of the reactants nor on the initial/final concentrations of the products.

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Balancing Chemical Equation<br> Na+Br2=NaBr
solniwko [45]

Answer:

2Na + Br2 = 2NaBr

Explanation:

In order to balance a chemical equation you make the make sure both sides have the same number of atoms on each side, you do this by multiplying on both sides as if it was a algebraic equation.

Na+ Br2 = NaBr

Na × 2 = Na2

Na × 2 = Na2

Br × 2 = Br2

2Na + Br2 = 2NaBr

Hope this helps.

7 0
3 years ago
In step 2, of the experiment, the procedure uses 3.0M NaOH. However, the student notices that the only solution of NaOH is conce
Luda [366]

Answer:

We need 78.9 mL of the 19.0 M NaOH solution

Explanation:

Step 1: Data given

Molarity of the original NaOH solution = 19.0 M

Molarity of the NaOH solution we want to prepare = 3.0 M

Volume of the NaOH solution we want to prepare = 500 mL = 0.500 L

Step 2: Calculate volume of the 19.0 M NaOH solution needed

C1*V1 = C2*V2

⇒with C1 = the concentration of the original NaOH solution = 19.0 M

⇒with V1 = the volume of the original NaOH solution = TO BE DETERMINED

⇒with C2 = the concentration of the NaOH solution we want to prepare = 3.0 M

⇒with V2 = the volume  of the NaOH solution we want to prepare = 500 mL = 0.500 L

19.0 M * V2 = 3.0 M * 0.500 L

V2 = (3.0 M * 0.500L) / 19.0 M

V2 = 0.0789 L

We need 0.0789 L

This is 0.0789 * 10^3 mL = 78.9 mL

We need 78.9 mL of the 19.0 M NaOH solution

8 0
3 years ago
NEED HELP! what is a orbital . describe
olchik [2.2K]

Answer:

In chemistry and quantum mechanics, an orbital is a mathematical function that describes the wave-like behavior of an electron, electron pair, or (less commonly) nucleons. An orbital can contain two electrons with paired spins and is often associated with a specific region of an atom.

Explanation:

6 0
4 years ago
How many moles of dipyrithione contain 8.2 x 10^24 atoms of N
Pani-rosa [81]
Dipyrithione is a chemical with formula, C₁₀H₈N₂O₂S₂. This means that each molecule of the substance has two (2) atoms of nitrogen. By using the dimensional analysis and Avogadro's number, equal to 6.022 x 10²³, we calculate for the answer as shown below.

    n = (8.2 x 10²⁴ atoms N)(1 molecule dipyrithione/ 2 atoms of N)(1 mole dipyrithione/ 6.022 x 10²³ molecules dipyrithione)

Simplifying,
  n = 6.8 moles dipyrithione

<em>ANSWER: 6.8 moles</em>
4 0
4 years ago
A sample of helium gas is heated from 20.0°C to 40.0°C. This
Montano1993 [528]

Answer:

C. 548mL

Explanation:

Attached is an image of the explanation. Hope this helps!

8 0
3 years ago
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