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irga5000 [103]
2 years ago
15

Anhydrous copper sulphate can be used in a test for water. What two things will happen when water is added to anhydrous copper s

ulphate?
Chemistry
1 answer:
Misha Larkins [42]2 years ago
3 0

Answer:

thanks bro for helping me thanku so much

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From the addition of water to the molecule of an alkene is obtained a product containing 21.6% O2. Write the addition reaction.
klemol [59]

Addition reaction between water molecules and alkene molecules produces alcohol.

<h3>What is addition reaction?</h3>

Addition reaction generally takes place across the unsaturated carbon compounds.

When water molecule (H₂O) is added to the alkene which may be ethene (C₂H₄) molecule then formation of product i.e. ethanol (CH₃CH₂OH) takes place through the addition of hydrogen and hydroxyl group across the double bond. And reaction is shown in the attached image.

Hence formation of alcohol product takes place.

To know more about addition reaction, visit the below link:

brainly.com/question/27487475

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2 years ago
What determines the strength of a dipole dipole force?
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Answer:

The more polar the molecules, the stronger the force. The more hydrogen in the molecule, the stronger the force.

Explanation:

I hope this helps and please ask if you need further help!

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3 years ago
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References Use the References to access important values if needed for this question A student ran the following reaction in the
ANTONII [103]

Answer:

19.27

Explanation:

Some values are corrected from correct source.Thus,

Moles of SO₂ = 8.19x10⁻² moles

Moles of O₂ = 8.10x10⁻² moles

Volume = 1 L

Molarity=\frac{Moles\ of\ solute}{Volume\ of\ the\ solution}

Concentration of SO₂ = 8.19x10² M

Concentration of O₂ = 8.10x10 M

Considering the ICE table for the equilibrium as:

                    2SO₂ (g) +    O₂ (g)     ⇔          2SO₃ (g)

t = o              8.19x10⁻²      8.19x10⁻²

t = eq                -2x                  -x                      2x

--------------------------------------------- --------------------------

neq:    8.19x10⁻² -2x       8.19x10⁻² -x                      2x

Given:  

Equilibrium concentration of  O₂ = 5.98x10⁻² M  = 8.19x10⁻² -x

Thus, x = 0.0212 M

[SO₂] = 8.19x10⁻² - 2*0.0212 = 0.0395 M

[SO₃] = 2*0.0212 = 0.0424 M

The expression for the equilibrium constant is:

K_c=\frac {[SO_3]^2}{[SO_2]^2[O_2]}  

K_c=\frac{{0.0424}^2}{{0.0395}^2\times 0.0598}  

K = 19.27

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3 years ago
Which form of energy represents a moving fan blades?!?!?
gregori [183]

Answer:

Mechanical I believe is the answer.

Explanation:

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