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Rom4ik [11]
2 years ago
7

The volume of a sample of oxygen is 300.0 mL, when the pressure is 1.00 atm and the temperature is 300K. At what pressure will t

he volume be 1000.0 mL and a temperature of 500K?
Chemistry
1 answer:
Brut [27]2 years ago
4 0

Answer:

The new pressure is 0.5 atm

Explanation:

Step 1: Data given

Volume of oxygen = 300 mL = 0.300 L

Pressure = 1.00 atm

Temperature = 300 K

The volume increases to 1000mL = 1.00 L

The temperature increases to 500 K

Step 2: Calculate the new pressure

(P1*V1)/T1 = (P2*V2)/T2

⇒with P1 = the initial pressure = 1.00 atm

⇒with V1 = the initial volume = 0.300 L

⇒with T1 = the initial temperature = 300 K

⇒with P2 = the new pressure = TO BE DETERMINED

⇒with V2 = the increased volume = 1.00 L

⇒with T2 = the increased temperature = 500 K

(1.00 atm* 0.300 L)/300 K = (P2 * 1.00L) / 500 K

P2 = (1.00 *0.300 * 500) / (300 *1.00)

P2 = 0.5 atm

The new pressure is 0.5 atm

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Answer:

How to prepare Magnesium Carbonate:

Explanation:

Magnesium carbonate can be prepared in laboratory by reaction between any soluble magnesium salt and sodium bicarbonate: MgCl2(aq) + 2NaHCO3(aq) → MgCO3(s) + 2NaCl(aq) + H2O(l) + CO2(g)

8 0
3 years ago
If you were about 10 kilometers above earth, what would the pressure approximately be?
Sliva [168]

Answer:

About 25 kPa  

Explanation:

Pressure decreases with height above sea level.

The calculation is rather complicated, so I will refer to the figure below.  

It shows that the pressure at 10 km is about 25 kPa.

7 0
3 years ago
what are two or more substances that are together in the same place, but are not chemically combined in a set ratio. They can be
GuDViN [60]
Yahoo has the answer to that question. because i looked it up on yahoo..
6 0
2 years ago
How to determine Km and Vm from a graph
ElenaW [278]

Answer:

From the graph find the maximum velocity and half it i.e. Vmax/2. Draw a horizontal line from this point till you find the point on the graph that corresponds to it and read off the substrate concentration at that point. This will give the value of Km.

5 0
2 years ago
The effusion rate of hcl is 43.2 cm/min in a certain effusion apparatus. what is the rate of effusion of ammonia in the same app
Jlenok [28]

The effusion rate is 1.125 cm/sec for ammonia.

How to find effusion rate ?

Effusion rate (r1) HCl = 43.2 cm/min

Molar mass (m2) NH3 =17.04g/mole

Molar mass (m1)  HCl    =36.46g/mole

  • Substitute the molar masses of the gases into Graham's law and solve for the ratio.
  • r1÷r2=√m2÷m1

       firstly convert 43.2 cm/min into cm/sec i.e., 0.72 cm/sec

      Then,

      0.72/r2 =√17.04/36.46

      r2= 1.125 cm/sec

Hence, the rate of diffusion of ammonia is 1.125 times faster than the rate of diffusion of hydrogen chloride.

learn more about effusion here:

brainly.com/question/2097955

#SPJ4

5 0
1 year ago
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