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3 years ago

What is the right way to sleep

Physics

2 answers:

kow [346]3 years ago

6 0

On a nice soft bed after a nice hot shower

nignag [31]3 years ago

5 0

Answer:

by lying down on a nice and soft quilted matress

You might be interested in

nlexa [21]

Answer:

By using Pythagoras Formula

Explanation:

Measure the distance man is sliding. “It will be c”

Measure the distance of between the tower and a post with which wire is attached. It will be “b”

Then apply Pythagoras Formula c2=a2 + b2 and solve it.

It will give the height of tower.

7 0

3 years ago

What is the general pattern of the planetary distances from the sun

eimsori [14]

Answer:

The Titius–Bode law (sometimes termed just Bode's law) is a hypothesis that the bodies in some orbital systems, including the Sun's, orbit at semi-major axes in a function of planetary sequence. The formula suggests that, extending outward, each planet would be approximately twice as far from the Sun as the one before.

Explanation:

8 0

4 years ago

a rocket burns propellant at a rate of dm/dt = 3.0 kg/s, ejecting gases with a speed of 8000 m/s relative to the rocket. Find th

elena-s [515]

Answer: 24 kN

Explanation:

Given

The rocket burns propellant at the rate of

$\dfrac{dm}{dt}=3\ kg/s$

Relative ejection of gases $v=8000\ m/s$

The magnitude of thrust force is given by

$F_t=v\dfrac{dm}{dt}\\\\F_t=8000\times 3=24,000\ N\ or\ 24\ kN$

5 0

3 years ago

If the same satellite orbited at the same velocity around a planet with three times the force of gravity, the orbit radius would

belka [17]

Answer:

the orbit radius would be divided by 3

Explanation:

In order to orbit the planet, the centripetal force of satellite must balance the gravitational force between planet and satellite.

centripetal Force = Gravitational Force

(Ms)(V)²/r = (G)(Ms)(Mₓ)/r²

V² = GMₓ/r

where,

V = velocity of satellite

G = Gravitational Constant

Mₓ = Mass of Planet

r = orbit radius

but, G = gr²/Mₓ

Therefore,

V² = (Mₓ/r)(gr²/Mₓ)

V = √gr --------------------- equation (1)

where,

g = force of gravity

Now, for change in force of gravity:

V' = √g'r'

where,

g' = 3g

V' = V

Therefore,

V = √3gr' ---------------- equation (2)

Comparing equation (1) and equation (2), we get:

√gr = √3gr'

gr = 3gr'

r = 3r'

r' = r/3

<u>Hence, the orbit radius would be divided by 3.</u>

5 0

3 years ago

Suppose a convex mirror has a focal length of 120 cm. A candle sits directly in front of the mirror. If the image of that candle

Andru [333]

We can solve the problem by using the mirror equation:
$\frac{1}{f} = \frac{1}{d_o}+ \frac{1}{d_i}$
where
f is the focal length
$d_o$ is the distance of the object from the mirror
$d_i$ is the distance of the image from the mirror

For the sign convention, the focal length is taken as negative for a convex mirror:
$f=-120 cm$
and the image is behind the mirror, so virtual, therefore its sign is negative as well:
$d_i=-24 cm$
putting the numbers in the mirror equation, we find the distance of the object from the mirror surface:
$\frac{1}{d_o} = \frac{1}{f}- \frac{1}{d_i}= \frac{1}{-120 cm} - \frac{1}{-24 cm}= \frac{1}{30 cm}$
So, the distance of the object from the mirror is $d_o = 30 cm$

8 0

4 years ago