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vovikov84 [41]
3 years ago
8

What effect do shiny metals have on radiant energy?

Physics
2 answers:
laiz [17]3 years ago
6 0

<u>In</u><u> </u><u>simple</u><u> </u><u>words</u>, Shiny metals reflects radiant energy.

  • It can reflect, scatter, absorb, or transmit energy.
  • As the metal surface is shiny, it does not emit radiant energy.
  • The lustrous metals conduct heat radiation e.i., Iron, copper.
Andreyy893 years ago
4 0

Answer:

Metals conduct heat and reduce the kinetic energy within the components that need to remain cool

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You are the science officer on a visit to a distant solar system. Prior to landing on a planet you measure its diameter to be 1.
babymother [125]

Answer:

Mass of the planet = 1.48 × 10²⁵ Kg

Mass of the star = 5.09 × 10³⁰ kg

Explanation:

Given;

Diameter = 1.8 × 10⁷ m

Therefore,

Radius = \frac{\textup{Diameter}}{\textup{2}}  = \frac{\textup{1.8}\times10^7}{\textup{2}}

or

Radius of the planet = 0.9 × 10⁷ m

Rotation period = 22.3 hours

Radius of star = 2.2 × 10¹¹ m

Orbit period = 407 earth days = 407 × 24 × 60 × 60 seconds = 35164800 s

free-fall acceleration = 12.2 m/s²

Now,

we have the relation

g = \frac{\textup{GM}}{\textup{R}^2}

g is the free fall acceleration

G is the gravitational force constant

M is the mass of the planet

on substituting the respective values, we get

12.2 = \frac{6.67\times10^{-11}\times M}{(0.9\times10^7)^2}

or

M = 1.48 × 10²⁵ Kg

From the Kepler's law we have

T² = \frac{\textup{4}\pi^2}{\textup{G}M_{star}}(R_{star})^3

on substituting the respective values, we get

35164800² = \frac{\textup{4}\pi^2}{6.67\times10^{-11}\timesM_{star}}(2.2\times10^{11})^3

or

M_{star} = 5.09 × 10³⁰ kg

6 0
3 years ago
Match the words in the left-hand column to the appropriate blank in the sentences in the right-hand column. use each word only o
sp2606 [1]
<span>1. About a trillion comets are thought to be located far, far beyond pluto in the Oort cloud. Oort cloud is theoretical cloud of predominantly icy planetesimals and. Many scientists have a belief that it surrounds the Sun at the distance of approximately between 50,000 and 200,000 AU. Such forces as  passing stars and of the Milky Way usually easily affect the outer Oort cloud and dislodge comets right from their orbits through the Oort the cloud and then they send them to the the inner Solar System.
2. The bright spherical part of a comet observed when it is close to the sun is the coma. When coma is viewed by a telescope it looks quite fuzzy and, unlike the stars, it does not have legible form. Such a phenomenon as the coma is created when a comet comes too close to the sun, then a comet warms and sublimes its parts. These parts are placed  around  the nucleus of a comet forming sort of envelope.
3. A comet's plasma tail stretches directly away from the sun. Both coma and comet's tail are visible parts of a comet, and when the comet passes through the inner Solar System we it becomes visible right from Earth. Usually comets have two tails :the blue plasma tail and the red dust tail. The plasma tail is formed by an interaction between the solar wind and the cometary plasma. And the dust tail is caused due to the activity of solar radiation pressure directed to the cometary dust.
</span>

4. A comet's nucleus is the frozen portion of a comet. The conet nucleus is  the solid center of the head of a comet that is also called ''dirty snowball'' or an ''icy dirtball'' among astronomists. It consists of rock, dust, and frozen gases and when they are heated by the Sun they form a coma (which is an atmosphere that surrounds nucleus) by sublimating of the gases.


5. Particles ejected from a comet can cause a meteor shower on Earth. A meteor shower is a celestial phenomenon during which we can see how meteors radiate. The meteors which we can observe are formed by meteoroids that enter Earth's atmosphere at extremely high speeds and they usually move in parallel directions. Some of the meteors are too small and often don't even reach the surface of Earth as they disintegrate during the entering process.

6. The Kuiper Belt extends from about beyond the orbit of neptune to about twice the distance of neptune from the sun.  It is the circumstellar disc that uccurs in the Solar System beyond the already known planets. Its formreminds of asteroid belt, but it is far larger, to be more exact in 20 times. I

5 0
3 years ago
what are the main morphological types of galaxies, and what is the difference in their rotation patterns?
ankoles [38]

The main morphological types of galaxies are elliptical, spiral, and irregular.

Based on their morphology , galaxies have been classified into 3 types namely elliptical, spiral, and irregular.

These galaxies have various sizes and shapes ranging from dwarf galaxies to giant galaxies.

Elliptical Galaxy:

  • The shape of it is generally circular
  • These are the largest among all the types of galaxies because according to astronomers, it is formed by the merger of other small galaxies.
  • Their rotational pattern is symmetric.

Spiral Galaxy:

  • A spiral galaxy consists of a bright nucleus surrounded by a thin outer disk forming a spiral shape.
  • This type of galaxy is the most common in our universe.
  • It is divided into three classes: Spiral a, Spiral b, and Spiral c.
  • Their rotational pattern has circular symmetry.

Irregular Galaxy:

  • These types of galaxies have no central nucleus and irregular arms which are bluish.
  • They don’t have any rotational symmetry.

To know more about "galaxies", refer to the following link:

brainly.com/question/24836631?referrer=searchResults

#SPJ4

3 0
2 years ago
What is the current at P? <br> A 0.17A<br> B 0.26A<br> C 0.43A<br> D 1.38A
UkoKoshka [18]

Answer:

ykfhti6d and smart ways of 666 and smart ways of learning and smart ways of learning and smart ways of learning is

Explanation:

dhhdhdh 6g and smart ways of learning and smart ways of learning and smart ways of learning and smart ways of learning and smart ways of learning and smart ways of learning and smart ways of learning and smart ways

8 0
3 years ago
A car slows down from 27.7 m/s to 10.9 m/s in 2.37 s, what is the acceleration?
larisa [96]

Answer:

Answer. to final velocity 'v' =10.9 m/s in time 't' = 2.37 secs. So acceleration = -7.09 m/sec^2 or, decceleration is 7.09 m/sec^2

Explanation:

4 0
3 years ago
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