What is 5a equivalent to

There are 32 forwards and 80 guards in Leo's basketball league.

The greatest common factor is the product of shared primes of the numbers prime factorizations.

32=2*2*2*2*2, 80=2*2*2*2*5 So the GCF is 2*2*2*2=16

So there will be 16 teams with 2 forwards and 5 guards each.

4 0

3 years ago

Read 2 more answers

Sketch the graph of the given equation. y = x2 + 8x +15

Tamiku [17]

The pictures may be in a different order for you but it’s the 3rd graph where the minimum is (-4,-1)

3 0

3 years ago

Solve for a. 3a/2<24 1)a=16 2)a>16 3)a<16 4)a>-16

Nady [450]

Answer:

a < 16

Step-by-step explanation:

4 0

2 years ago

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Does 10p/2q = 5p/q I think it is not equal but it doesn't seem right.

motikmotik

Answer:

Yes, those two are equal.

Step-by-step explanation

(10p/2q)*2/2=5p/q

5 0

4 years ago

Scores on the SAT Mathematics test are believed to be normally distributed. The scores of a simple random sample of five student

AysviL [449]

Answer:

The mean calculated for this case is $\bar X=584$

And the 95% confidence interval is given by:

$584-2.776\frac{86.776}{\sqrt{5}}=476.271$

$584+2.776\frac{86.776}{\sqrt{5}}=691.729$

So on this case the 95% confidence interval would be given by (476.271;691.729)

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

$\bar X$ represent the sample mean for the sample

$\mu$ population mean (variable of interest)

s represent the sample standard deviation

n represent the sample size

Solution to the problem

The confidence interval for the mean is given by the following formula:

$\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}$ (1)

In order to calculate the mean and the sample deviation we can use the following formulas:

$\bar X= \sum_{i=1}^n \frac{x_i}{n}$ (2)

$s=\sqrt{\frac{\sum_{i=1}^n (x_i-\bar X)}{n-1}}$ (3)

The mean calculated for this case is $\bar X=584$

The sample deviation calculated $s=86.776$

In order to calculate the critical value $t_{\alpha/2}$ we need to find first the degrees of freedom, given by:

$df=n-1=5-1=4$

Since the Confidence is 0.95 or 95%, the value of $\alpha=0.05$ and $\alpha/2 =0.025$ , and we can use excel, a calculator or a tabel to find the critical value. The excel command would be: "=-T.INV(0.025,4)".And we see that $t_{\alpha/2}=2.776$

Now we have everything in order to replace into formula (1):

$584-2.776\frac{86.776}{\sqrt{5}}=476.271$

$584+2.776\frac{86.776}{\sqrt{5}}=691.729$

So on this case the 95% confidence interval would be given by (476.271;691.729)

3 0

3 years ago