To answer this question, you need to know <span>Graham's Law of Effusion/Diffusion formula. In this formula, the rate of diffusion/effusion would be influenced by the mass. As the molecule has bigger mass, the rate should be slower because it will be harder to pass the membrane. The calculation should be:</span>
<span>Rate 1 / Rate 2 = √[M2/M1]
</span>4.11/1= √[M2/2]
M2=33.78 g/mol
Answer:
O Option 1
Explanation:
IF ENERGY IS RELEASED, THEN ENERGY RELEASED SHOULD BE SUBTRACTED FROM ORIGINAL.
(16.32 X 10^-19) - (5.4 X 10^-19)
10.92 X 10^-19
C. 6, 1, 0, -1/2
Explanation:
The four quantum numbers are:
- Principal quantum number (n): this represents the energy level in which an orbital is located.
- Azimuthal quantum number gives the shape of the orbitals in subshells accommodating the electrons.
- Magnetic quantum number gives the number of spatial orientations or degeneracy of the orbitals in the subshells.
- Spin quantum number describes the spinning of an electron in either clockwise or anticlockwise directions.
To know the electron with the highest energy, we use the principal quantum number values.
n values takes whole numbers i.e n = 1,2,3,4,5,6,7.............
The higher the value, the higher the energy level.
From the given quantum numbers, C has the highest energy levels.
Learn more;
Quantum numbers brainly.com/question/9288609
#learnwithBrainly
Answer:
0.84 moles of oxygen are required.
Explanation:
Given data:
Mass of CO₂ produced = 37.15 g
Number of moles of oxygen = ?
Solution:
Chemical equation:
C + O₂ → CO₂
Number of moles of CO₂:
Number of moles = mass/molar mass
Number of moles = 37.15 g/ 44 g/mol
Number of moles = 0.84 mol
Now we will compare the moles of oxygen and carbon dioxide.
CO₂ : O₂
1 : 1
0.84 : 0.84
0.84 moles of oxygen are required.
20 grams is probably the mass
