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k0ka [10]
3 years ago
10

What is the product of 1 5/7 * 3 2/3?

Mathematics
2 answers:
Degger [83]3 years ago
8 0

Answer:

GJG

Step-by-step explanation:

HGJG

True [87]3 years ago
6 0
The product is 3 10/22
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There's on 38000 there? is it meant to be 380000?
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3 years ago
What is 6 more than 7 times a number is 41
son4ous [18]


the problem would be set up as 6+(7*x)=41

first u take off the number 6 by subtracting it from itself to cancel it out then u do the same to the number 41

7x =41 now u need to cancel out the number 7 attatched to the x so u divikde it by itself and then do the same to the other side so 41 divided by 7 =5.9

 so x =5.9

8 0
3 years ago
X²+Y²=250 and XY=117<br> What are the values of X and Y?
yan [13]

Answer:

<h3>            x = -9,  y = -13 </h3><h3>    or    x = 13,   y = 9</h3><h3>    or    x = -13,  y = -9</h3><h3>    or     x = 9,   y = 13</h3>

Step-by-step explanation:

x^2+y^2=250\\\\x^2-2xy+y^2+2xy=250\\\\(x-y)^2=250-2xy\\\\(x-y)^2=250-2\cdot117\\\\ (x-y)^2=16\\\\x-y=4\qquad\qquad\vee\qquad \qquad  x-y=-4\\\\x=4+y \qquad\qquad \vee\qquad\qquad x=-4+y\\\\(y+4)y=117\qquad\vee\qquad\quad (y-4)y=117\\\\y^2+4y-117=0\qquad\vee\qquad y^2-4y-117=0\\\\y=\dfrac{-4\pm\sqrt{4^2-4(-117)}}{2\cdot1}\qquad\vee\qquad y=\dfrac{4\pm\sqrt{4^2-4(-117)}}{2\cdot1}\\\\y=\dfrac{-4\pm\sqrt{16+468}}{2}\qquad\ \ \vee\qquad y=\dfrac{4\pm\sqrt{16+468}}{2}

y_1=\dfrac{-4-22}{2}\ ,\quad y_2=\dfrac{-4+22}{2}\ ,\quad y_3=\dfrac{4-22}{2}\ ,\quad y_4=\dfrac{4+22}{2}\\\\y_1=-13\ ,\qquad y_2=9\ ,\qquad\quad\qquad\ y_3=-9\ ,\qquad y_4=13\\\\x_{1,2}=4+y_{1,2}\qquad\qquad\qquad\qquad\qquad x_{3,4}=-4+y_{3,4}\\\\x_1=-9\ ,\qquad x_2=13\ ,\qquad\quad\qquad x_3=-13\ ,\qquad x_4=9

6 0
3 years ago
Explain how to plot the point (3, –7) on the coordinate plane.
Reil [10]
Coordinates are written in the form (x,y), x being a certain length along the horizontal x axis and y being a certain height along the vertical y axis. Positive y numbers are in the top half of the plane and negative y numbers are on the bottom. Positive x numbers are on the right side of the plane and negative x numbers are on the left. Therefore, (3,-7) would be 3 across to the right from the origin (where the x and y axes intersect) at (3,0) and 7 downwards from that point to (3,-7).
5 0
3 years ago
Read 2 more answers
Number line , need help! Merry Christmas!
Kruka [31]

Answer:

It is A ( sister helped me if it does not work it is B) \

Have a great day and MERRY CHRISTMAS!!!

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
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