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Galina-37 [17]
3 years ago
15

Tasha rolls a 7.0 bowling ball down down the alley for the league championship. One pin is still standing, and Jeanne hits it he

ad-on with a velocity of 9.0 m/s . The 2.0pin acquires a forward velocity of 14.0m/s. . What is the new velocity of the bowling ball
Physics
1 answer:
Alona [7]3 years ago
8 0
<h2>Answer:5ms^{-1}</h2>

Explanation:

Let u_{1} be the velocity of the bowling ball before collision.

Let u_{2} be the velocity of the pin before collision.

Let v_{1} be the velocity of the bowling ball after collision.

Let v_{2} be the velocity of the pin after collision.

Let m_{1} be the mass of the bowling ball.

Let m_{2} be the mass of the pin.

According to the conservation of momentum,

m_{1}u_{1}+m_{2}u_{2}=m_{1}v_{1}+m_{2}v_{2}

Given,

m_{1}=7Kg\\m_{2}=2Kg\\u_{1}=9ms^{-1}\\u_{2}=0ms^{-1}\\v_{2}=14ms^{-1}

7(9)+2(0)=7(v_{1})+2(14)

7v_{1}=35\\v_{1}=5ms^{-1}

New velocity of bowling ball is 5ms^{-1}

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