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3 years ago

The ______ is the time it takes for a wave to complete one cycle.

Physics

2 answers:

EastWind [94]3 years ago

5 0

It is called the period

kykrilka [37]3 years ago

4 0

Answer:

time period

Explanation:

The time period is defined as the time taken by a wave to complete one cycle.

Its SI unit is second.

It is the reciprocal of frequency.

Frequency is defined as the number of cycles completed in one second.

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Help needed,

Elena L [17]

Answer:

224 J

Explanation:

Step one:

given data

Force applied = 22.4 N

distance = 10 meters

<u>Required:</u>

the work done

Step two:

The expression for the work done is

WD= force*distance

substitute

WD= 22.4*10

WD= 224 J

3 0

3 years ago

A plant cell is no longer capable of capturing energy from sunlight and converting it into chemical energy. Which organelle is m

Nadya [2.5K]

The chloroplast of the cell is most likely damaged if the plant cell is no longer capable of capturing energy from sunlight and converting it into chemical energy.

The chloroplast is the structure inside the leaf cell that is known for capturing light energy from the sun.

This light energy is then used to make food that has chemical energy. If a plant cell has a damaged chloroplast or the chloroplast is removed, then it will no longer be able to trap the light energy. As a result, the process of photosynthesis will not occur in the plant cell. The plant cell will not be able to make the chemical energy required for functioning.

To learn more about chloroplast, click here:

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#SPJ4

8 0

1 year ago

Physics question i appreciate your help please

Mice21 [21]

The vector c is the answer
Answer choice A

8 0

3 years ago

Read 2 more answers

30 POINTS! HELP!!! WILL MARK BRAINLIEST

Tanzania [10]

Answer:gravity

Explanation:

6 0

3 years ago

A helix with 17 turns has height H and radius R. Charge is distributed on the helix so that the charge density increases like (i

marishachu [46]

The total charge on the helix is

Q = $\frac{221}{2}\sqrt{(\frac{H}{17})^2+(2\piR)^2$

Height of one turn = $\frac{H}{n}$

Horizontal distance in one turn = $2\pi R$

<h3>length of spring in one turn is</h3>

$l = \sqrt{h^2+(2\piR)^2}\\\\
l = \sqrt{(\frac{H}{n})^2+(2\piR)^2}
$

So, the total length of spring

$L = n*l\\\\
L = n * \sqrt{(\frac{H}{n})^2+(2\piR)^2}
$

Therefore, charge on spring

$Q = \frac{1}{2}*L*(13-0)\\\\
Q = \frac{1}{2}*n\sqrt{(\frac{H}{n})^2+(2\piR)^2}*13\\\\
Q = \frac{1}{2}*17*13\sqrt{(\frac{H}{17})^2+(2\piR)^2}\\\\
Q = \frac{221}{2}\sqrt{(\frac{H}{17})^2+(2\piR)^2\\\\
$

For more information on linear charge density, visit

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8 0

2 years ago