Anyone need help with math i not that good with word problems but i could help

Mathematics

1 answer:

Setler79 [48]3 years ago

7 0

sure. or u could google them...

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Chloe reads 7 pages of a mystery book in 9 minutes. What is her average reading rate in pages per

myrzilka [38]

Answer:

1.25

Step-by-step explanation:

you have to take the 9 pages and divide by 7 and then divide that by 60 and u get 1.25

4 0

1 year ago

A circle is centered at the point (-3,2) and passes through the point (1,5). What is the radius of the circle?

Akimi4 [234]

Answer:

Step-by-step explanation:

The radius is a distance on a circle from the center to a point on the circle.

We have both of these points describe here in this definition. Using the distance formula will give us the radius.

$\sqrt{(x \text{ difference })^2+(y \text{ difference})^2$

The difference between 1 and -3 is 1-(-3)=4.

The difference between 5 and 2 is 5-2=3.

$\sqrt{4^2+3^2}$

$\sqrt{16+9}$

$\sqrt{25}$

$5$

8 0

2 years ago

Help I am very bad at math I need answers by tomorrow if you can help please do

d1i1m1o1n [39]

Answer:

Step-by-step explanation:

(a - b)(a +b) = a² - b²

1 - Sin² A = Cos² A

$LHS = \frac{1}{1- Sin A} + \frac{1}{1 + Sin A}\\\\= \frac{1*(1 + Sin A)}{(1- Sin A)(1 + Sin A)} + \frac{1*(1- Sin A)}{(1 + Sin A)(1- Sin A)}\\\\= \frac{1 + Sin A+ 1 - Sin A}{1^{2}- Sin^{2} A}\\\\= \frac{2}{1 - Sin^{2} A}\\\\= \frac{2}{Cos^{2} A}\\\\= 2 Sec^{2} A$

2) Sec² A - Tan² A = 1

$LHS = \frac{1}{Sec A - Tan A}\\\\=\frac{1*(Sec A + Tan A)}{(Sec A - Tan A)(Sec A + Tan A)}\\\\=\frac{Sec A + Tan A}{Sec^{2} A - Tan^{2} A}\\\\=\frac{Sec A + Tan A }{1}\\\\= Sec A + Tan A = RHS\\\\\\$

3) LHS = Cosec² A + Cot² A

= Cosec² A + Cosec² A - 1

= 2Cosec² A - 1 = RHS

$4) LHS = \frac{Sec A}{Cos A}- \frac{Tan A}{Cot A}\\\\ = Sec A*\frac{1}{Cos A}-Tan A*\frac{1}{Cot A}\\\\ = Sec A * Sec A - Tan A * Tan A\\\\= Sec^{2} A - Tan^{2} A \\\\= 1$