Answer:
i don't know but have a good day
Answer:
Distance = πr
Displacement = 2r
Explanation:
First we need to find the distance covered by the car. As the car is travelling on a circular path and it traveled to a diametrically opposite point on the circular path. Therefore, the distance covered by the car must be the half value of the circumference.
Distance = Circumference/2
Distance = 2πr/2
<u>Distance = πr</u>
Since, displacement is the straight line distance between two points. So, the displacement in moving from a point to its diametrically opposite point must be equal to the diameter of circle:
Displacement = Diameter
<u>Displacement = 2r</u>
For the steady flow process, the first law is written like
DH + Du2/2 + gDz = Q + Ws
since there is no shaft work, Ws = 0
and flow is horizontal, Dz = 0
Therefore,
DH + Du2/2 = Q
substituting for the quantities,
(2726.5 - 334.9) x 1000 + (200^2 - 3^2)/2 = Q (in terms of J/kg)
Q = 2411.1 kJ/kg
Heat transferred through the coil per unit mass of water = 2411.1 kJ
Answer:
Acceleration is the rate of change of velocity. What is commonly said as ‘ten meter per second squared’ can bee broken down into ‘ten meter per second per second.’ This gives us the true meaning of the term acceleration.
Just like ‘ten meter per second’ means increasing the displacement by ten meters every second, ‘ten meter per second per second’ means increasing the velocity by ten meters per second every second.
So, basically if you consider the case of a free fall motion, where ‘t’ stands for time and ‘v’ stand for velocity at that instant:
At,
t=0, v=0 m/s
t=1, v=0+10 m/s;
t=2, v=0+10+10 m/s;
t=3, v=0+10+10+10 m/s;
This can also be thought as a Arithmetic Progression where common difference ‘D’ is the acceleration(a), since it adds a 10 m/s to velocity every second and the first term ‘A’ stands for the initial velocity (u). Using this approach we can derive to the first equation of motion:
v = u + at
Hope this Answer Helps!!
Explanation:
plz mark me as a brainlest and thank my answer
Answer:
The third charge placed is 0.80 m.
Explanation:
Given that,
Distance = 0.57 m
First charge = q
Third charge = 2q
We need to calculate the electrostatic force on charge q₁ due to q₂
Using formula of electrostatic force
When placed another charge q₃ at certain distance from origin, then the net force on charge q₁ due to both charges is
The net electrostatic force on the charge at the origin doubles.
Put the value into the formula
Hence, The third charge placed is 0.80 m from origin in x-axis.
