3M^2 + 11MN + 6N^2 = 3M^2 + 2MN + 9MN + 6N^2
= M(3M + 2N) + 3N(3M + 2N) = (3M + 2N)(M + 3N)
Answer: 3M^2 + 11MN + 6N^2 = (3M + 2N)(M + 3N)
Given:
A circle of radius r inscribed in a square.
To find:
The expression for the area of the shaded region.
Solution:
Area of a circle is:

Where, r is the radius of the circle.
Area of a square is:

Where, a is the side of the square.
A circle of radius r inscribed in a square. So, diameter of the circle is equal to the side of the square.

So, the area of the square is:


Now, the area of the shaded region is the difference between the area of the square and the area of the circle.




Therefore, the correct option is (a).
Answer:

Step-by-step explanation:
Notice that we are in the presence of an arithmetic sequence (there is a common difference of 6 between a term and the next). So thisis an arithmetic sequence with first term
. and common difference "<em>d</em>" = 6.
Recall now the formula for the nth term (
) of an arithmetic sequence:

Then, using our values in the formula, we get:
