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lisov135 [29]
3 years ago
10

Points A and B are to be mapped onto a number line according to two equations. The solutions to the equation 2/3A=-24 is the coo

rdinate of point A. Tje solution to the equation 20=-B/0.2 is the coordinate of point B. Solve the first equation to find the coordinate of point A. Show your work
Mathematics
1 answer:
Ymorist [56]3 years ago
4 0

Answer:

\boxed{A=-36} \\ \\ \boxed{B=4}

Step-by-step explanation:

In mathematics, a number line is graph of a straight line that shows a representation of real numbers. In this problem, points A and B are to be mapped onto a number line according to two equations. So we can find these two points by isolating A from the first equation and B from the second one as follows:

\frac{2}{3}A=-24 \\ \therefore A=\frac{3(-24)}{2} \\ \\ \therefore \boxed{A=-36}

20=\frac{-B}{0.2} \\ \\ \therefore B=-(0.2)(20) \\ \\ \therefore \boxed{B=4}

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-sqrt(36) = -6

Hope this helps :)
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3 years ago
Solve for n. -4(n+5)=8
il63 [147K]

Answer:

Simplify first:

-4n - 20 = 8

Add 20 to both sides:

-4n = 28

Divide by -4:

Therefore you will get:

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<span>9.99p + 6.67p ≤ 30
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What are the coordinates of the treasure? If necessary, round the coordinates to the nearest tenth.
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3 years ago
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The product of $7d^2-3d+g$ and $3d^2+hd-8$ is $21d^4-44d^3-35d^2+14d-16$. What is $g+h$?
galina1969 [7]
<h2>Answer:</h2><h2>g = 2  and h = -5</h2>

Step-by-step explanation:

To find the product with unknown values of variables, multiply the terms and equate the value to the given product.

(7d^{2} - 3d + g)(3d^{2} + hd - 8) = 21d^{4}  + 7hd^{3} - 56d^{2} - 9d^{3} - 3hd^{2} + 24d + 3gd^{2} + ghd - 8g

(7d^{2} - 3d + g)(3d^{2} + hd - 8)     = 21d^{4}  + (7h-9) d^{3} + (3g-56-3h)d^{2}  + (24+gh)d -8g   ... (1)

Comparing eq(1) to the product given in question,

-8g = -1

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24 + 2h = 14

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3 0
3 years ago
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