Need help plzzzz....need this done by today

Mathematics

1 answer:

ddd [48]3 years ago

5 0

For this case, we must indicate which of the given graphs corresponds to the following inequality:

$y\geq 1-3x$

If we substitute the point $(x, y) = (0,0)$ we have:

$0> = 1-3 (0)\\0> = 1$

It is not met, so we discard options A and C.

It is observed that the lines of option B and D correspond to the equation $y = 1-3x$ . But the dotted line of option B indicates that the region given by: $y> 1-3x$ is plotted

Thus, the region that indicates $y\geq 1-3x$ is option D

Answer:

Option D

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What is the quotient StartFraction 15 p Superscript negative 4 Baseline q Superscript negative 6 Baseline Over negative 20 p Sup

zhannawk [14.2K]

Answer:

$- \frac{3}{4} \times \frac{p^{8} }{q^{3} }$

Step-by-step explanation:

We have to find the quotient of the following division, $\frac{15p^{-4}q^{-6} }{- 20p^{-12} q^{-3}}$ .

Now, $\frac{15p^{-4}q^{-6} }{- 20p^{-12} q^{-3}}$

= $- \frac{3}{4} p^{[- 4 - (- 12)]} q^{[-6 - (- 3)]}$ {Since all the terms in the expression are in product form, so we can treat them separately}