You first wanna find <BAD, because if AB is perpendicular to AC, then it has to form a 90 degree angle. So 90-56=34 degrees. So now you have a 34 & 63 degrees in the ABD triangle. In a triangle, all angles add up to equal 180 degrees. So 34+63+x=180...and x=83. So <ADB= 83 degrees. Now you want to find angle ADC...which you can just subtract 83 from 180 (because <ADB & <ADC forms 180 degree angle). You will then get 97 as angle ADC. So, the same thing as before, add up 56+97+x=180, because all angles (in the triangle ADC) add up to be 180 degrees. X will then equal 27 degrees. Angle ACB= 27 degrees.
(Y-Y1)/(X-X1)
(-9-(-29))/(7-15)
20/-8
-2 1/2
The slope is -2 1/2
Answer:
D(-5,3) and E(-5,1)
Step-by-step explanation:
|AB|² = (-1-5)² + (-6-2)²
|AB|² = 36 + 64
|AB|² = 100
|AB| = 10
AB/DE = 5
|DE| = 10/5 = 2
D(-5,3) and E(-5,1)
|DE|² = (-5+5)² + (3-1)²
|DE|² = 4
|DE| = 2
Verified
Subtract 8p from 9p and then rewrite the equation. Then you add 7 to 4 and rewrite the equation again. Then you divide 1p by 11 and get p=11.
Answer:
680 girls and 850 boys
Step-by-step explanation:
the ratio of girls is 4/9
then we can find the number of girls (G) in the group of 1530 students using proportions:
4 / 9 = G / 1530
solving for G by multiplying both sides of the proportion by 1530, we get:
G = 4 * 1530 / 9 = 680
So there were:
680 girls and 1530 - 680 = 850 boys
