Assume that a 15-kg ball moving at 8 m/s strikes a wall perpendicularly and rebounds elastically at the same speed. What is the
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Star B is closer than star A, because 1/ 0.58 = 1.72 pc, while 1/.73 = 1.36 pc.
<h3>What is stellar parallax and distance measurement using stellar parallax?</h3>To calculate the distances to nearby stars, astronomers employ a phenomenon known as parallax. The apparent displacement of an object due to a change in the viewer's point of view is known as parallax. The distances between close stars can be calculated using this phenomenon. A nearer star will seem to move against the farther-off background stars as the Earth revolves around the Sun. By measuring a star's position once, then again six months later, astronomers can establish the apparent shift in location of that star. The apparent motion of the star is referred to as stellar parallax.
A straightforward correlation exists between the distance of a star and parallax angle:
The distance d and parallax angle p are both measured in parsecs and arcseconds, respectively.
Stellar parallax of star A= 0.58 arcseconds
Stellar parallax of star B= 0.73 arcseconds
So, on applying the formula,
The distance of the star A= 1.72pc
And the distance of the star B= 1.36pc
Therefore, star B is closer than star A.
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Answer:
The second law of a vibrating string states that for a transverse vibration in a stretched string, the frequency is directly proportional to the square root of the string's tension, when the vibrating string's mass per unit length and the vibrating length are kept constant
The law can be expressed mathematically as follows;
The second law of the vibrating string can be verified directly, however, the third law of the vibrating string states that frequency is inversely proportional to the square root of the mass per unit length cannot be directly verified due to the lack of continuous variation in both the frequency, 'f', and the mass, 'm', simultaneously
Therefore, the law is verified indirectly, by rearranging the above equation as follows;
From which it can be shown that the following relation holds with the limits of error in the experiment
m₁·l₁² = m₂·l₂² = m₃·l₃² = m₄·l₄² = m₅·l₅²
Explanation: