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3 years ago

This has me confused help please

Mathematics

1 answer:

Nesterboy [21]3 years ago

7 0

Answer:

x = 30

Step-by-step explanation:

Since the triangles are congruent then corresponding angles are congruent.

∠ B ≅ ∠ E

The sum of the 3 angles in Δ CDE = 180°, thus

∠ E = 180° - (55 + 65)° = 180° - 120° = 60°

Thus

2x = 60 ( divide both sides by 2 )

x = 30

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Kim and Sam went to Mexico Restaurant for lunch. The total bill was $21.58. They decide to leave an 18% tip. How much will the t

GrogVix [38]

Answer:

$3.88

Step-by-step explanation:

You want to leave a 18% tip on a meal that cost $21.58.

First, convert the 18% to an actual number that can be used in a calculation. For percents,this is always done by simply dividing the percent (in this case 18%) by 100%.So, the conversational term "18%" becomes 18% / 100% = 0.18 in terms of a real mathematical number.

Second, you need to find out what 18% of your $21.58 meal cost is.This is always done by multiplying 0.18 by $21.58, or 0.18 x $21.58=$3.88.

So, the amount of tip you are going to leave is $3.88.

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3 years ago

Calculate the surface area of a solid box in the shape of a cube with<br> side length 3cm.

RoseWind [281]

Answer:

54 cm^2

Step-by-step explanation:

side ( a ) = 3 cm

Formula : -

Surface area ( cube ) = 6a^2

Surface area ( cube )

= 6 x ( 3 )^2

= 6 x 9

= 54 cm^2

6 0

3 years ago

Read 2 more answers

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qaws [65]

its a virus dont fall for it

Step-by-step explanation:

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3 years ago

Consider the equation below. f(x) = 2x3 + 3x2 − 336x (a) Find the interval on which f is increasing. (Enter your answer in inter

Vaselesa [24]

We have been given a function $f(x)=2x^3+3x^2-336x$ . We are asked to find the interval on which function is increasing and decreasing.

(a). First of all, we will find the critical points of function by equating derivative with 0.

$f'(x)=2(3)x^{2}+3(2)x^1-336$

$f'(x)=6x^{2}+6x-336$

$6x^{2}+6x-336=0$

$x^{2}+x-56=0$

$x^{2}+8x-7x-56=0$

$(x+8)-7(x+8)=0$

$(x+8)(x-7)=0$

$x=-8,x=7$

So $x=-8,7$ are critical points and these will divide our function in 3 intervals $(-\infty,-8)U(-8,7)U(7,\infty)$ .

Now we will find derivative over each interval as:

$f'(x)=(x+8)(x-7)$

$f'(-9)=(-9+8)(-9-7)=(-1)(-16)=16$

Since $f'(9)>0$ , therefore, function is increasing on interval $(-\infty,-8)$ .

$f'(x)=(x+8)(x-7)$

$f'(1)=(1+8)(1-7)=(9)(-6)=-54$

Since $f'(1)$ , therefore, function is decreasing on interval $(-8,7)$ .

Let us check for the derivative at $x=8$ .

$f'(x)=(x+8)(x-7)$

$f'(8)=(8+8)(8-7)=(16)(1)=16$

Since $f'(8)>0$ , therefore, function is increasing on interval $(7,\infty)$ .

(b) Since $x=-8,7$ are critical points, so these will be either a maximum or minimum.

Let us find values of f(x) on these two points.

$f(-8)=2(-8)^3+3(-8)^2-336(-8)$

$f(-8)=1856$

$f(7)=2(7)^3+3(7)^2-336(7)$

$f(7)=-1519$

Therefore, $(-8,1856)$ is a local maximum and $(7,-1519)$ is a local minimum.

Let us find 2nd derivative.

$f''(x)=6(2)x^{1}+6$

$f''(x)=12x+6$

$12x+6=0$

$12x=-6$

$\frac{12x}{12}=-\frac{6}{12}$

$x=-\frac{1}{2}$

Therefore, $x=-\frac{1}{2}$ is an inflection point of given function.

3 0

3 years ago

Part A: Solve –mk – 90 > 85 for m. Show your work.

erma4kov [3.2K]

Answer:

A) m < -175/k and B) 3c/5 - 11

Step-by-step explanation:

A) Add 90 to both sides. -mk > 175.

Next, divide both sides by -k. Because you divide by a negative, don't forget to reverse the sign!

m < -175/k.

B) Subtract 3c from both sides.

-5f = 55 - 3c.

Now multiply both sides by -1/5.

f = 3c/5 - 11

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3 years ago