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Darya [45]
3 years ago
9

Help please I don’t understand this at all

Chemistry
2 answers:
yuradex [85]3 years ago
8 0

Answer:Lewis structures, also known as Lewis dot diagrams, Lewis dot formulas, Lewis dot structures, electron dot structures, or Lewis electron dot structures (LEDS), are diagrams that show the bonding between atoms of a molecule and the lone pairs of electrons that may exist in the molecule.

Explanation:

https://www.google.com/search?safe=active&sa=G&hl=en-AE&q=lewis+dot+structure+for+socl2&tbm=isch&tbs=simg:CAQSkwEJl6wkhaCF8RwahwELEKjU2AQaAAwLELCMpwgaYgpgCAMSKLQIgAqhFJ4UvgixCJsU_1wmaFNod2T3wM8A_1yz3FPbk0zD3vM9Y05DMaMJIe1rmByndy3ehNceWPZ_1Os6vuhBUMa0uIVD-c7WuS5sBQ9-NE65K8_1W_1LARdfaQyAEDAsQjq7-CBoKCggIARIEzN3JyAw&ved=0ahUKEwjZn6O3jNfiAhUPxoUKHa3LD-0Qwg4ILSgA

Paladinen [302]3 years ago
7 0
I think you must do dot and cross diagrams but im not sure at all
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aseous methane will react with gaseous oxygen to produce gaseous carbon dioxide and gaseous water . Suppose 5.5 g of methane is
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Answer:

There is 9.6 grams of CO2 produced

Explanation:

Step 1: Data given

Mass of methane = 5.50 grams

Molar mass of methane = 16.04 g/mol

Mass of oxygen = 13.9 grams

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Step 2: The reaction

CH4(g) + 2O2(g) → CO2(g) + 2H2O(g)

Step 3: Calculate number of moles

Moles = mass / molar mass

Moles methane = 5.50 grams / 16.04 g/mol

Moles methane = 0.343 moles

Moles oxygen = 13.9 grams / 32.0 g/mol

Moles oxygen = 0.434 moles

For 1 mol CH4 we need 2 moles O2 to produce 1 mol CO2 and 2 moles H2O

O2 is the limiting reactant. It will completely react (0.434 moles).

There will react 0.434/2 = 0.217 moles CH4

There will remain 0.343-0.217 = 0.126 moles CH4

There will be produced 0.434 moles of H2O and

0.434/2 =0.217 moles of CO2

Step 4: Calculate mass of products

Mass = moles * molar mass

Mass CO2 = 0.217 moles ¨44.01 g/mol

Mass CO2 = 9.6 grams

Mass H2O = 0.434 moles * 18.02

Mass H2O = 7.8 grams

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