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Darya [45]
3 years ago
9

Help please I don’t understand this at all

Chemistry
2 answers:
yuradex [85]3 years ago
8 0

Answer:Lewis structures, also known as Lewis dot diagrams, Lewis dot formulas, Lewis dot structures, electron dot structures, or Lewis electron dot structures (LEDS), are diagrams that show the bonding between atoms of a molecule and the lone pairs of electrons that may exist in the molecule.

Explanation:

https://www.google.com/search?safe=active&sa=G&hl=en-AE&q=lewis+dot+structure+for+socl2&tbm=isch&tbs=simg:CAQSkwEJl6wkhaCF8RwahwELEKjU2AQaAAwLELCMpwgaYgpgCAMSKLQIgAqhFJ4UvgixCJsU_1wmaFNod2T3wM8A_1yz3FPbk0zD3vM9Y05DMaMJIe1rmByndy3ehNceWPZ_1Os6vuhBUMa0uIVD-c7WuS5sBQ9-NE65K8_1W_1LARdfaQyAEDAsQjq7-CBoKCggIARIEzN3JyAw&ved=0ahUKEwjZn6O3jNfiAhUPxoUKHa3LD-0Qwg4ILSgA

Paladinen [302]3 years ago
7 0
I think you must do dot and cross diagrams but im not sure at all
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A car traveled 1500 km from Dallas to Shreveport in 4 hours. What is its average speed?
Gennadij [26K]

Answer:

\frac{1500 \: km}{4 \: hours}  = 375 \: km \: per \: hour.

5 0
1 year ago
A radioactive substance of mass 768g has a half life of 3 years. After how many years does it leave only 6g undecayed?​
vagabundo [1.1K]

Answer:

The answer is 21 years.

Explanation:

7×3

8 0
2 years ago
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How many molecules are in 92.9 g of NaOH?​
kirza4 [7]

2.3226678127494718

this number you could probably simplify to your own standards on your own.

5 0
3 years ago
In an ionic compound, the size of the ions affects the internuclear distance (the distance between the centers of adjacent ions)
jeyben [28]

Answer:

Li2S> Na2S> K2S> CsS

Explanation:

The lattice energy of ionic species depends on the relative sizes of ions in the ionic compounds. As the size of ions increases, the lattice energy decreases and vice versa.

When the size of the anions are the same, the lattice energy now depends on the relative sizes of the cations. Therefore, since all the compounds are sulphides and the order of magnitude of ionic sizes is: Li^+ < Na^+ < K^+ < Cs^+.

Therefore, the order of decrease in lattice energy is; Li2S> Na2S> K2S> CsS

7 0
3 years ago
Iron (III) oxide and hydrogen react to form iron and water, like this: Fe 03(s)+3H9)2Fe(s)+3HO) At a certain temperature, a chem
belka [17]

The question is incomplete, here is the complete question:

Iron (III) oxide and hydrogen react to form iron and water, like this:

Fe_2O_3(s)+3H_2(g)\rightarrow 2Fe(s)+3H_2O(g)

At a certain temperature, a chemist finds that a 8.9 L reaction vessel containing a mixture of iron(III) oxide, hydrogen, Iron, and water at equilibrium has the following composition.

Compound             Amount

  Fe₂O₃                     3.95 g

     H₂                        4.77 g

     Fe                        4.38 g

    H₂O                      2.00 g

Calculate the value of the equilibrium constant Kc for this reaction. Round your answer to 2 significant digits.

<u>Answer:</u> The value of equilibrium constant for given equation is 1.0\times 10^{-4}

<u>Explanation:</u>

To calculate the molarity of solution, we use the equation:

\text{Molarity of the solution}=\frac{\text{Mass of solute}}{\text{Molar mass of solute}\times \text{Volume of solution (in L)}}

  • <u>For hydrogen gas:</u>

Given mass of hydrogen gas = 4.77 g

Molar mass of hydrogen gas = 2 g/mol

Volume of the solution = 8.9 L

Putting values in above expression, we get:

\text{Molarity of hydrogen gas}=\frac{4.77}{2\times 8.9}\\\\\text{Molarity of hydrogen gas}=0.268M

  • <u>For water:</u>

Given mass of water = 2.00 g

Molar mass of water = 18 g/mol

Volume of the solution = 8.9 L

Putting values in above expression, we get:

\text{Molarity of water}=\frac{2.00}{18\times 8.9}\\\\\text{Molarity of water}=0.0125M

For the given chemical equation:

Fe_2O_3(s)+3H_2(g)\rightarrow 2Fe(s)+3H_2O(g)

The expression of equilibrium constant for above equation follows:

K_{eq}=\frac{[H_2O]^3}{[H_2]^3}

Concentration of pure solids and pure liquids are taken as 1 in equilibrium constant expression.

Putting values in above expression, we get:

K_{c}=\frac{(0.0125)^3}{(0.268)^3}\\\\K_{c}=1.0\times 10^{-4}

Hence, the value of equilibrium constant for given equation is 1.0\times 10^{-4}

6 0
3 years ago
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