Answer:
0.03697 mol Al₂(SO₄)₃
General Formulas and Concepts:
<u>Chemistry - Atomic Structure</u>
- Reading a Periodic Table
- Using Dimensional Analysis
Explanation:
<u>Step 1: Define</u>
12.65 g Al₂(SO₄)₃
<u>Step 2: Identify Conversions</u>
Molar Mass of Al - 26.98 g/mol
Molar Mass of S - 32.07 g/mol
Molar Mass of O - 16.00 g/mol
Molar Mass of Al₂(SO₄)₃ - 2(26.98) + 3(32.07) + 12(16.00) = 342.17 g/mol
<u>Step 3: Convert</u>
<u />
= 0.03697 mol Al₂(SO₄)₃
<u>Step 4: Check</u>
<em>We are given 4 sig figs. Follow sig fig rules and round.</em>
We already have 4 sig figs in the final answer, so no need to round.
State the given:
Moles of Sulfur = 5 moles
Molar mass of Sulfur = 32.06g/mol
Look through the formulas:
Moles = Mass/Molar Mass
Rearrange the equation:
Mass = Moles x Molar mass
Plug in your given:
5 moles Sulfur x <u>32.06g</u>
1 mol
<u>= 160.3g of Sulfur</u>
<u>Answer:</u> The new volume of the tank is 4.67 L
<u>Explanation:</u>
To calculate the volume when temperature and pressure has changed, we use the equation given by combined gas law.
The equation follows:
where,
are the initial pressure, volume and temperature of the gas
are the final pressure, volume and temperature of the gas
We are given:
![P_1=114kPa\\V_1=15L\\T_1=115^oC=[115+273]K=388K\\P_2=250kPa\\V_2=?\\T_2=-8^oC=[-8+273]K=265K](https://tex.z-dn.net/?f=P_1%3D114kPa%5C%5CV_1%3D15L%5C%5CT_1%3D115%5EoC%3D%5B115%2B273%5DK%3D388K%5C%5CP_2%3D250kPa%5C%5CV_2%3D%3F%5C%5CT_2%3D-8%5EoC%3D%5B-8%2B273%5DK%3D265K)
Putting values in above equation, we get:
Hence, the new volume of the tank is 4.67 L
The system will then shift to the left, making more reactants.
