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vova2212 [387]
3 years ago
7

Pete saves 4/5 of his wages each week.If he earns 150$ per week. How much did he save ?

Mathematics
1 answer:
yulyashka [42]3 years ago
5 0

solution:

4/5 of $150

4/5 x 150

=120

so Pete saves $120 per week

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20 POINTS! WILL MAKE BRAINLIEST
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1.a sphere with a radius of three units

 
By definition, the volume of a sphere is:
 V = ( \frac{4}{3} ) (\pi) (r ^ 3)

 Substituting values we have:
 V=(\frac{4}{3})(\pi)(3^3)
 Rewriting we have:
 V = (4) (\pi) (3 ^ 2)

V = (4) (\pi) (9)

V = 36\pi

 2.a cone with a diameter of twelve units and a height of three units
 
 By definition, the volume of a cone is given by:
 V =  \frac{1}{3}  (\pi) (r ^ 2) (h)

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3 years ago
Round the fraction to 0, 1/2, or 1.<br><br><br><br> 9/10
marishachu [46]

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3 years ago
Solve for x please!
Elina [12.6K]

x^2 = 81/100

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The container that holds the water for the football team is
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3 0
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Read 2 more answers
1) On a standardized aptitude test, scores are normally distributed with a mean of 100 and a standard deviation of 10. Find the
Musya8 [376]

Answer:

A) 34.13%

B)  15.87%

C) 95.44%

D) 97.72%

E) 49.87%

F) 0.13%

Step-by-step explanation:

To find the percent of scores that are between 90 and 100, we need to standardize 90 and 100 using the following equation:

z=\frac{x-m}{s}

Where m is the mean and s is the standard deviation. Then, 90 and 100 are equal to:

z=\frac{90-100}{10}=-1\\ z=\frac{100-100}{10}=0

So, the percent of scores that are between 90 and 100 can be calculated using the normal standard table as:

P( 90 < x < 100) = P(-1 < z < 0) = P(z < 0) - P(z < -1)

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It means that the PERCENT of scores that are between 90 and 100 is 34.13%

At the same way, we can calculated the percentages of B, C, D, E and F as:

B) Over 110

P( x > 110 ) = P( z>\frac{110-100}{10})=P(z>1) = 0.1587

C) Between 80 and 120

P( 80

D) less than 80

P( x < 80 ) = P( z

E) Between 70 and 100

P( 70

F) More than 130

P( x > 130 ) = P( z>\frac{130-100}{10})=P(z>3) = 0.0013

8 0
3 years ago
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