The area of a rhombus is 1/2 times the lengths of the diagonals
A = (1/2)(AC)(BD)
Since the diagonals bisect each other, and ed = 8, BD must be 16. Substituting in this for BD and the given area (168) we get the following:
168 = (1/2)(AC)16
168 = 8(AC)
21 = AC
2+_3/458 find the product
8.5+8.6=73.1÷2=36.55
formula for midpont a+b divide 2
Answer:
D
Step-by-step explanation: