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Elden [556K]
3 years ago
6

The Central Limit Theorem: states that the average range can be used as a proxy for the standard deviation. states that the aver

age of assignable variations is zero. controls the steepness of an operating characteristic curve. is the theoretical foundation of the c-chart. allows managers to use the normal distribution as the basis for building some control charts.
Business
1 answer:
pickupchik [31]3 years ago
4 0

The correct answer is - allows managers to use the normal distribution as the basis for building some control charts.

<u>Explanation:</u>

It is the theorem that allows inference from a random sample. It says that:

• The sample mean will likely be towards the population mean within a margin of error

• The margin of error is a multiple of the standard error, which is the standard deviation divided by the square root of the sample size. The multiple is determined by the degree of statistical confidence you’re looking for, and the normal deviate corresponding to that — 1.65 for 90% confidence, 1.96 for 95% confidence, etc.

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A car dealer who sells only late-model luxury cars recently hired a new salesman and believes that this salesman is selling at l
Natasha2012 [34]

Answer:

t=\frac{5000-5600}{\frac{800}{\sqrt{16}}}=-3      

Explanation:

Data given and notation      

\bar X=5000 represent the sample mean      

s=800 represent the standard deviation for the sample      

n=16 sample size      

\mu_o =5600 represent the value that we want to test    

\alpha represent the significance level for the hypothesis test.    

t would represent the statistic (variable of interest)      

p_v represent the p value for the test (variable of interest)  

State the null and alternative hypotheses.      

We need to conduct a hypothesis in order to determine if the mean is lower than 5600, the system of hypothesis would be:      

Null hypothesis:\mu \geq 5600      

Alternative hypothesis:\mu < 5600      

We don't know the population deviation, so for this case is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:      

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}} (1)      

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".  

Calculate the statistic      

We can replace in formula (1) the info given like this:      

t=\frac{5000-5600}{\frac{800}{\sqrt{16}}}=-3      

4 0
3 years ago
Seth invested $20,000 in Series EE savings bonds on April 1. By December 31, the published redemption value of the bonds had inc
11Alexandr11 [23.1K]

Answer:

700 for interest

Explanation:

6 0
3 years ago
Cartier corporation currently sells its products for $50 per unit. the company's variable costs are $20 per unit. fixed expenses
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The answer is 40%, in which the following are given: the Variable expense is equal to 20 dollars per unit and Sales is equal to 50 dollars per unit. Use the formula Variable Expense Ratio = Variable Expenses / Sales to get the answer. 

Variable Expense Ratio = Variable Expenses / Sales
Variable Expense Ratio = 20 dollars per unit / 50 dollars per unit
Variable Expense Ratio = 40 %

The variable expense ratio is an expression of variable production costs of the company as a percentage of sales, calculated as variable expense divided by total sales. It compares a cost that alters with levels of production to the number of revenues generated by production.
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kykrilka [37]

Answer:

The ethical dilemma that Marco Manager is facing having to choose between trying to keep an existing friendship (at least he believes that they are friends) or doing the right thing as a manager, which would involve investigating why the money is missing and most certainly firing the employee.

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3 years ago
“formal evaluation could include testing the predictive capabilities of the models on observed data to see how effective and eff
Neporo4naja [7]
This is known as in-sample forecast. It estimated the model using all available data and then comparing it to the model's fixed values to the actual realizations. But, this method is known to attract an overly positive picture of the model's forecasting ability since common fitting algorithms tend to take pains to avoid big prediction errors and are also inclined to overfitting (mistaking noise for signal in the data).
7 0
3 years ago
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