Use the ICE table approach as solution:
PbSO₄ --> Pb²⁺ + SO₄²⁻
I - 0 0
C - +s +s
E - s s
Ksp = [Pb²⁺][SO₄²⁻]
1.82×10⁻⁸ = s²
Solving for s,
s = <em>1.35×10⁻⁴ M</em>
Answer:
the limiting reagent is butane
Explanation:
5C₄H₁₀ + 25O₂ → 20CO₂ + 5H₂0
According to Arrhenius Theory of acids and bases, an Arrhenius base produces OH-.
Among the four options, (3) LiOH is the correct one because it can separate into Li+ and OH- when being put in water.
Hope this helps~
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