The theoretical yield of 18 gram of is 162 gram of .
The amount of a product produced by a reaction is generally expressed as a percentage of the reaction's yield. The amount of product that stoichiometry predicts is known as the theoretical yield, but the amount that would be actually achieved is known as the actual yield.
The balanced chemical equation is :
→
It is known that the molar mass of water is 18 gram /mol and 2 gram per mole of .
18g (1 mol (/2 g ()(2 mol / 2 mol ()(18 g /1 mol ) = 162 g .
Theoretical yield will be 162 gram.
So, the theoretical yield of 18 gram of is 162 gram of .
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B. Ca(OH)2 - (Calcium Hydroxide)
Explanation:
1 literThe total of water is equal to 1000.0 g of water
we need to find the molality of a solution containing 10.0 g of dissolved in Na₂S0₄1000.0 g of water
1. For that find the molar mass
Na: 2 x 22.99= 45.98
S: 32.07
O: 4 x 16= 64
The total molar mass is 142.05
We have to find the number of moles, y
To find the number of moles divide 10.0g by 142.05 g/mol.
So the number of moles is 0.0704 moles.
For the molarity, you need the number of moles divided by the volume. So, 0.0704 mol/1 L.
The molarity would end up being 0.0704 M
The molality of a solution containing 10.0 g of Na2SO4 dissolved in 1000.0 g of water is 0.0704 Mliter
Answer:
-219.99kJ
Explanation:
The acronym '' NADH'' simply stands for what is known as coenzyme 1 with full meaning of Nicotinamide Adenine Dinucleotide Hydride. This substance is useful in the production of energy. The oxidation reaction of NADH causes it to produce NADP⁺ and the oxygen produces water when it is in the reduction process. The balanced equation for the oxidation reaction is given below as:
NADPH ---------------------------------------------------------------------> NADP⁺H⁺ + 2e⁻.
Also, the balanced equation for the reduction reaction is given below as:
O₂ + 2H⁺ + 2e⁻ --------------------------------------------------------------> H₂O.
It can be shown from the above REDOX reaction that the total number of electrons getting transferred is 2.
The Gibbs energy = -nFE. where n = 2, F = faraday's constant = 96485.3329 C and E = overall cell potential.
The overall cell potential = E[ reduction reaction] - E[oxidation reaction] = 0.82 - (- 0.32 ) = 1.14 V.
Hence, the Gibbs energy = - 2 × 96485.3329 × 1.14 = -219.99kJ