Y’’(x)= 6x + 1
y’(x)= 3x^2 + x + 2
y(x)= x^3 + 1/2x^2 + 2x + 5
What picture........................
z 5 − z+2 2z+4 =−3 space, startfraction, 5, divided by, z, end fraction, minus, start fraction, 2, z, plus, 4, divided by, z
yan [13]
Answer:
The sum of all the possible values for z that satisfy the above equation is -5.
Step-by-step explanation:
The given equation is

We need to find the sum of all the possible values for z that satisfy the above equation.
The given equation can be rewritten as

Cancel out common factors.

Add 2 on both sides.



Multiply both sides by -1.

Only z=-5 satisfy the given equation.
Therefore the sum of all the possible values for z that satisfy the above equation is -5.
N=3
Because 6+6=12
Hope this helps